The area of the base of a cone is 64π cm2 while its slant height is 17 cm. This cone is remoulded to obtain a solid sphere. The radius of this sphere will be:
2 \(\sqrt[3]{30}\) cm
8 \(\sqrt[3]{30}\) cm
6.5 cm
2 \(\sqrt[3]{40}\) cm
When a solid object is remoulded into another shape, its volume remains constant. Therefore, we need to calculate the volume of the cone first. From the given area of the base and slant height, we can find the radius and height of the cone. Once the volume of the cone is known, we equate it to the volume of a sphere to find the radius of the sphere.
Find the radius of the cone:
The area of the base of a cone is given by the formula \(A = \pi r^2\), where \(r\) is the radius of the base.
Given area of the base \( = 64\pi \text{ cm}^2\).
So, \( \pi r^2 = 64\pi \text{ cm}^2 \).
Dividing by \( \pi \) on both sides, we get:
\( r^2 = 64 \text{ cm}^2 \)
\( r = \sqrt{64} \text{ cm} \)
\( r = 8 \text{ cm} \)
Find the height of the cone:
The relationship between the radius (\(r\)), height (\(h\)), and slant height (\(l\)) of a cone is given by the Pythagorean theorem: \(l^2 = r^2 + h^2\).
Given slant height \(l = 17 \text{ cm}\) and we found \(r = 8 \text{ cm}\).
So, \( 17^2 = 8^2 + h^2 \)
\( 289 = 64 + h^2 \)
\( h^2 = 289 - 64 \)
\( h^2 = 225 \)
\( h = \sqrt{225} \text{ cm} \)
\( h = 15 \text{ cm} \)
Calculate the volume of the cone:
The volume of a cone is given by the formula \(V_{\text{cone}} = \frac{1}{3} \pi r^2 h\).
Substituting the values \(r = 8 \text{ cm}\) and \(h = 15 \text{ cm}\):
\[ V_{\text{cone}} = \frac{1}{3} \pi (8 \text{ cm})^2 (15 \text{ cm}) \]
\[ V_{\text{cone}} = \frac{1}{3} \pi (64 \text{ cm}^2) (15 \text{ cm}) \]
\[ V_{\text{cone}} = \pi (64 \text{ cm}^2) \left(\frac{15}{3}\right) \text{ cm} \]
\[ V_{\text{cone}} = \pi (64 \text{ cm}^2) (5 \text{ cm}) \]
\[ V_{\text{cone}} = 320\pi \text{ cm}^3 \]
Equate the volume of the cone to the volume of the sphere:
When the cone is remoulded into a solid sphere, their volumes are equal.
Let \(R\) be the radius of the sphere.
The volume of a sphere is given by the formula \(V_{\text{sphere}} = \frac{4}{3} \pi R^3\).
So, \(V_{\text{sphere}} = V_{\text{cone}}\)
\[ \frac{4}{3} \pi R^3 = 320\pi \text{ cm}^3 \]
Divide both sides by \( \pi \):
\[ \frac{4}{3} R^3 = 320 \text{ cm}^3 \]
Multiply both sides by \( \frac{3}{4} \):
\[ R^3 = 320 \times \frac{3}{4} \text{ cm}^3 \]
\[ R^3 = 80 \times 3 \text{ cm}^3 \]
\[ R^3 = 240 \text{ cm}^3 \]
To find \(R\), take the cube root of 240:
\[ R = \sqrt[3]{240} \text{ cm} \]
We need to simplify \( \sqrt[3]{240} \). Find the prime factors of 240:
\( 240 = 24 \times 10 = (8 \times 3) \times (2 \times 5) = (2^3 \times 3) \times (2 \times 5) = 2^4 \times 3 \times 5 \)
\[ R = \sqrt[3]{2^3 \times 2 \times 3 \times 5} \text{ cm} \]
\[ R = 2 \sqrt[3]{2 \times 3 \times 5} \text{ cm} \]
\[ R = 2 \sqrt[3]{30} \text{ cm} \]
Correct Option: A) \(2 \sqrt[3]{30}\) cm
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Correct Option: B) 37
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Correct Option: C) Greater than 50%
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Correct Option: D) Kerala — Kerala is famously known as the "Spice Garden of India" due to its extensive cultivation of various spices and its historical significance in the global spice trade.
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Correct Option: B) 27.3
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