The value of 12 ÷ 3 × (7 + 8 – 3) is:
To solve this problem, we need to follow the order of operations, often remembered by the acronym BODMAS/PEMDAS. This rule dictates the sequence in which mathematical operations should be performed: Brackets/Parentheses, Orders/Exponents, Division and Multiplication (from left to right), and Addition and Subtraction (from left to right).
The expression inside the brackets is \( (7 + 8 - 3) \).
First, perform the addition: \( 7 + 8 = 15 \).
Then, perform the subtraction: \( 15 - 3 = 12 \).
So, the original expression becomes: \( 12 \div 3 \times 12 \).
The expression is now \( 12 \div 3 \times 12 \).
First, perform the division: \( 12 \div 3 = 4 \).
The expression becomes: \( 4 \times 12 \).
Now, perform the multiplication: \( 4 \times 12 = 48 \).
Thus, the value of the expression is 48.
Correct Option: A) 48
This problem involves analyzing inequalities to determine the truthfulness of given conclusions based on a provided statement. We need to combine the parts of the statement and then check each conclusion against the combined inequality.
The statement is given as: \(N > M \ge L = K < J\)
This can be broken down into individual inequalities:
From the statement, we have \(L = K\) and \(K < J\). Combining these, we get \(L < J\).
Therefore, Conclusion I (\(L > J\)) is false.
From the statement, we have \(N > M\) and \(M \ge L\).
Combining these two inequalities:
In both possible scenarios derived from \(M \ge L\), the relationship \(N > L\) holds true.
Therefore, Conclusion II (\(N > L\)) is true.
C) Only conclusion II is true
The question asks to identify the individual who launched the first Indian Virtual Science Lab for children under the CSIR Jigyasa programme. This is a factual question related to recent government initiatives and public figures.
B) Dr. Jitendra Singh launched India's first Virtual Science Lab for children under the CSIR Jigyasa programme. This initiative aims to provide a virtual platform for students to interact with scientists and explore scientific concepts.
The area of a rhombus can be calculated using the lengths of its diagonals. The formula for the area of a rhombus is half the product of the lengths of its diagonals.
Identify the given lengths of the diagonals.
Recall the formula for the area of a rhombus.
\[ \text{Area} = \frac{1}{2} \times d_1 \times d_2 \]Substitute the given values into the formula.
\[ \text{Area} = \frac{1}{2} \times 12 \text{ cm} \times 15 \text{ cm} \]Perform the multiplication.
\[ \text{Area} = 6 \text{ cm} \times 15 \text{ cm} \] \[ \text{Area} = 90 \text{ cm}^2 \]Correct Option: C) 90 cm²
To solve this problem, we need to track the person's movement in two dimensions (North-South and East-West) from the starting point L to the final point M. We will consider South as negative Y-direction, North as positive Y-direction, East as positive X-direction, and West as negative X-direction. We will calculate the net displacement in each direction.
The coordinates of point M are \((-45, 0)\) relative to point L \((0,0)\).
The displacement in the X-direction is \(-45\) m, which means 45 m West.
The displacement in the Y-direction is \(0\) m, which means no net displacement North or South.
Therefore, point M is 45 m to the West of point L.
Correct Option: C) 45 m, West
In chlor-alkali process, chlor represents chlorine gas and alkali represents:
The question asks to identify what "alkali" refers to in the chlor-alkali process. This requires knowledge of the chemical products formed during this industrial process.
Correct Option: A) NaOH is sodium hydroxide, which is a strong alkali produced in the chlor-alkali process.
To solve this problem, we need to follow a series of steps:
Original word: DESTROY
Identify vowels and consonants:
Apply transformation rules:
Let's transform each letter:
The new set of letters is: C, F, R, S, Q, P, X.
Arrange the new letters in alphabetical order:
C, F, P, Q, R, S, X
Find the fifth letter from the right end:
The ordered sequence is: C, F, P, Q, R, S, X
Counting from the right end:
The fifth letter from the right end is P.
Correct Option: A) P
The question asks to evaluate two statements regarding Mendeleev's approach to classifying elements based on their chemical properties. We need to determine if Mendeleev focused on compounds with carbon and hydrogen, and if his reason for selecting certain elements was their low reactivity.
Correct Option: B) Both statements are incorrect.
The question asks for the launch year of the Twenty Point Programme (TPP) in India. To answer this, one needs to recall the historical context of major government initiatives and their timelines.
Correct Option: B) 1975
The Twenty Point Programme (TPP) was indeed launched by the Government of India in 1975 by Prime Minister Indira Gandhi. It was conceived as a package of programmes to address various socio-economic challenges, primarily focusing on poverty alleviation and improving the quality of life for the common people.
The question asks to identify the physiographic division of India that stretches approximately 2500 km from the Indus River in the west to the Brahmaputra River in the east. This requires knowledge of the major physiographic divisions of India and their geographical extent.
Correct Option: C) Himalayan mountains