In this question, a group of numbers/symbols is coded using letters as per the table given below and the conditions which follow. The correct combination of codes following the condition is your answer.
| Number/Symbol | @ | % | ! | 4 | 2 | 5 | # | ? | + | = | 3 | & | 7 | < |
| Code | C | L | N | D | M | B | R | A | P | J | X | W | E | H |
Conditions:
(i) If the first element is a symbol and the last, a number, the codes for these two are to be interchanged.
(ii) If the first element is an odd number and the last, an even number, the first and last elements are to be coded as Ø.
(iii) If both second and third elements are either numbers or symbols, the third element is to be coded as the code for the second element.
How will “% + < 2 5 =” be coded?
The problem requires coding a given sequence of numbers and symbols based on a provided table and three specific conditions. We need to apply these conditions sequentially to the given sequence " % + < 2 5 = " and then find the final code.
D) L P P M B J
Wait, there's a discrepancy. Let's re-evaluate the question and my steps carefully. The question asks for the code for " % + < 2 5 = ". My derived code is L J J M B X. None of the options match this exactly. Let's re-read the table and conditions very carefully.
Re-evaluation:
Number/Symbol: @ % ! 4 2 5 # ? + = 3 & 7 <
Code: C L N D M B R A P J X W E H
Sequence: % + < 2 5 =
1. Initial Codes:
% \(\rightarrow\) L
+ \(\rightarrow\) J
< \(\rightarrow\) H
2 \(\rightarrow\) M
5 \(\rightarrow\) B
= \(\rightarrow\) X
Initial sequence of codes: L J H M B X
2. Condition (i): "If the first element is a symbol and the last, a number, the codes for these two are to be interchanged."
First element: % (symbol)
Last element: = (symbol)
The last element is not a number. So, Condition (i) does not apply.
3. Condition (ii): "If the first element is an odd number and the last, an even number, the first and last elements are to be coded as Ø."
First element: % (symbol)
The first element is not an odd number. So, Condition (ii) does not apply.
4. Condition (iii): "If both second and third elements are either numbers or symbols, the third element is to be coded as the code for the second element.\
The question asks to identify the sole note-issuing authority in India. This requires knowledge of the functions of various financial regulatory bodies in the country.
Correct Option: A) Reserve Bank of India is the central bank of India and holds the sole authority for issuing currency notes (except one-rupee notes and coins, which are issued by the Ministry of Finance but circulated by RBI).
The question asks to identify the mirror(s) that always form a virtual and erect image. We need to recall the image formation properties of convex mirrors, plane mirrors, and concave mirrors.
C) Both A and B. Both convex mirrors and plane mirrors always form virtual and erect images. Convex mirrors form virtual, erect, and diminished images, while plane mirrors form virtual, erect, and same-sized images.
The question asks for the specific temperature required to convert gypsum into Plaster of Paris. This conversion involves heating gypsum to remove a precise amount of its water of crystallization. Understanding the chemical reaction and the conditions for it is key.
Correct Option: B) The preparation of Plaster of Paris from gypsum requires heating gypsum to approximately \(100^\circ\text{C}\) (\(373\text{ K}\)). At this temperature, gypsum loses three-quarters of its water of crystallization to form calcium sulfate hemihydrate, which is Plaster of Paris.
The question asks to identify a specific type of parallelogram based on two properties: all sides are equal, and diagonals are unequal. We need to recall the definitions and properties of different quadrilaterals, especially parallelograms, to find the correct match.
Correct Option: B) A rhombus is a parallelogram with all four sides equal in length. Its diagonals are generally unequal, bisecting each other at right angles. If the diagonals were equal, it would be a square.
The question asks about the location of the respiratory pigment in the human body. The primary respiratory pigment in humans is hemoglobin, which is responsible for oxygen transport.
A) In red blood cells. Hemoglobin, the respiratory pigment responsible for oxygen transport in humans, is contained within red blood cells. These specialized cells are designed to carry oxygen efficiently throughout the body.
The question asks to identify an environmental factor that influences sex determination in some animals. This phenomenon is known as Environmental Sex Determination (ESD). We need to evaluate each option to see which one is a known factor for ESD.
Temperature is a crucial environmental factor that determines the sex of developing organisms in many species, particularly reptiles. This phenomenon is known as Temperature-dependent Sex Determination (TSD).
This problem involves Ohm's Law, which states that the current flowing through a conductor between two points is directly proportional to the voltage across the two points, and inversely proportional to the resistance between them. First, we will use the given initial current and potential difference to calculate the resistance of the appliance. Since the appliance remains the same, its resistance will be constant. Then, we will use this constant resistance and the new potential difference to find the new current drawn by the appliance.
According to Ohm's Law, \(V = IR\), where \(V\) is the potential difference, \(I\) is the current, and \(R\) is the resistance. We can rearrange this to find resistance:
\[ R = \frac{V_1}{I_1} \]\[ R = \frac{50 \text{ V}}{5 \text{ A}} \]\[ R = 10 \text{ } \Omega \]Since the resistance of the appliance remains constant, we can use Ohm's Law again with the new potential difference (\(V_2\)) and the calculated resistance (\(R\)) to find the new current (\(I_2\)):
\[ I_2 = \frac{V_2}{R} \]\[ I_2 = \frac{110 \text{ V}}{10 \text{ } \Omega} \]\[ I_2 = 11 \text{ A} \]D) 11 A is the correct answer. As calculated, when the potential difference is increased to 110 V, the current drawn by the appliance will be 11 A.
This problem involves finding the least common multiple (LCM) of the given time intervals. When events occur at regular intervals and we need to find when they will occur simultaneously again, the concept of LCM is applied. The LCM of the time intervals will give us the total time after which all three traffic lights will turn red simultaneously.
D) 8.33 a.m. is the correct answer because the LCM of 30, 45, and 60 seconds is 180 seconds, which is 3 minutes. Adding 3 minutes to 8:30 a.m. gives 8:33 a.m.
To find the profit or loss percentage, we first need to determine the cost price (CP) of one pen and the selling price (SP) of one pen. Once we have these values, we can calculate the profit or loss and then express it as a percentage of the cost price.
Mr. Saxena bought pens at Rs 150 a dozen. A dozen means 12 pens.
\[ \text{CP of 12 pens} = \text{Rs } 150 \]\[ \text{CP of 1 pen} = \frac{\text{Rs } 150}{12} = \text{Rs } 12.50 \]He sold them for Rs 15 each.
\[ \text{SP of 1 pen} = \text{Rs } 15 \]Since the Selling Price (Rs 15) is greater than the Cost Price (Rs 12.50), there is a profit.
The profit percentage is calculated on the Cost Price.
\[ \text{Profit Percentage} = \left( \frac{\text{Profit}}{\text{CP}} \right) \times 100\% \]\[ \text{Profit Percentage} = \left( \frac{2.50}{12.50} \right) \times 100\% \]\[ \text{Profit Percentage} = \left( \frac{250}{1250} \right) \times 100\% \]\[ \text{Profit Percentage} = \left( \frac{1}{5} \right) \times 100\% \]\[ \text{Profit Percentage} = 20\% \]A) 20% profit is the correct answer because the calculated profit percentage is 20%.