The question asks to identify a Sino-Tibetan language spoken in Northeast India from the given options. This requires knowledge of major language families in India and the geographical distribution of languages.
C) Bodo: Bodo is a prominent language spoken in the northeastern states of India, particularly in Assam. It belongs to the Tibeto-Burman branch of the Sino-Tibetan language family. It is one of the 22 scheduled languages of India.
Mendel's experiments with pea plants were groundbreaking in understanding inheritance. To achieve controlled crosses and study specific traits, he employed a precise methodology involving both cross-fertilisation and self-fertilisation. Understanding the sequence of these steps is key to identifying the correct statement.
A) Cross-fertilisation of plants was performed initially, followed by self-fertilisation. This statement accurately describes Mendel's experimental procedure. He first cross-pollinated pure-breeding parent plants to get the \(F_1\) generation and then allowed the \(F_1\) plants to self-pollinate to produce the \(F_2\) generation, which was crucial for observing the inheritance patterns.
The problem asks us to find the next number in the given series: 18, 19, 28, 53, 102, ?. We need to identify the pattern or rule governing the sequence of numbers.
The differences are 1, 9, 25, 49.
We can observe that these differences are perfect squares:
This sequence of squares \(1^2, 3^2, 5^2, 7^2\) indicates that the squares of consecutive odd numbers are being added to the previous term.
Following the pattern of odd numbers (1, 3, 5, 7), the next odd number is 9. So, the next difference should be \(9^2\).
\[ 9^2 = 81 \]To find the next term, we add this difference to the last given term (102).
\[ 102 + 81 = 183 \]Thus, the number that replaces the question mark is 183.
B) 183
In the given question, the statement is followed by two conclusions. Which of the two conclusion(s) is/are true based on the given statement?
Statement: $ < # = & ≤ @ > * = /
Conclusions:
I. * > &
II. # < /
Only conclusion II is true
Only conclusion I is true
Both conclusions I and II are true
Neither conclusion I nor II is true
The problem involves analyzing a set of inequalities and equalities to determine the truthfulness of two given conclusions. We need to combine the given relations and then check if the conclusions logically follow.
The statement is: \( < \# = \& \le @ > * = / \)
Let's break this down into individual relations:
Combining these, we get a chain of relations:
\[ < \# = \& \le @ > * = / \]From the statement, we have the following relevant relations:
\[ \& \le @ \text{ and } @ > * \]Combining these, we have \( \& \le @ > * \). This means that \( \& \) could be less than \( * \), equal to \( * \), or greater than \( * \). We cannot definitively conclude that \( * > \& \).
For example, if \( \& = 5 \), \( @ = 6 \), \( * = 4 \), then \( * < \& \).
If \( \& = 5 \), \( @ = 6 \), \( * = 5 \), then \( * = \& \).
If \( \& = 5 \), \( @ = 7 \), \( * = 6 \), then \( * > \& \).
Since we cannot definitively say \( * > \& \), Conclusion I is false.
From the statement, we have the following relevant relations:
\[ \# = \& \text{ and } \& \le @ \text{ and } @ > * \text{ and } * = / \]Now we need to determine the relationship between \( \# \) and \( / \), which is equivalent to determining the relationship between \( \& \) and \( * \).
We have \( \& \le @ > * \).
As established in the evaluation of Conclusion I, the relationship between \( \& \) and \( * \) cannot be definitively determined from \( \& \le @ > * \). Therefore, we cannot definitively conclude that \( \# < / \).
Conclusion II is false.
Since both Conclusion I and Conclusion II are false, neither conclusion is true.
D) Neither conclusion I nor II is true
To find the missing number in the series, we need to identify the pattern or rule governing the sequence of numbers. We will calculate the differences between consecutive terms to see if there's a consistent arithmetic progression or another mathematical relationship.
A) 108 is the correct answer. Following the identified pattern of second-order differences, the next term in the series is 108.
This question tests the understanding of osmosis, specifically plasmolysis, in plant cells. When a plant cell is placed in a hypertonic solution (a solution with a higher solute concentration than the cell's cytoplasm), water moves out of the cell due to osmosis, leading to shrinkage of the protoplast.
A) Cells will lose water and there will be shrinkage of contents of the cell away from the cell wall
This statement accurately describes plasmolysis. The strong sugar solution is hypertonic, causing water to move out of the cell by osmosis, leading to the shrinkage of the protoplast away from the cell wall.
This problem involves calculating the present value of a debt that is settled earlier than its due date. We need to find the amount that, if invested today at the given interest rate, would accumulate to the original debt amount by the original due date. This is a simple interest problem where we need to find the principal (present value) when the future value, interest rate, and time are known.
The debt is due in 1 year (12 months). The trader wants to settle it after 2 months. This means the payment is being made \(12 - 2 = 10\) months before the original due date. Therefore, we need to find the present value of ₹8,000 for a period of 10 months at 9% per annum.
Time \(t = 10\) months \( = \frac{10}{12}\) years \( = \frac{5}{6}\) years.
The future value (Amount) \(A\) is given by the formula:
\[ A = P \left(1 + \frac{Rt}{100}\right) \]where \(P\) is the Principal (present value), \(R\) is the rate of interest, and \(t\) is the time in years.
Rounded off to the nearest rupee, the amount to be paid is \(\text{₹}7,442\).
Correct Option: A) ₹7,442
To solve this problem, we first need to convert the train's speed from km/h to m/s. Then, we can use the formula \(\text{Distance} = \text{Speed} \times \text{Time}\) to find the length of the train. Once the train's length is known, we can calculate the time it takes for the train to cross an electric pole, which is equivalent to the time it takes to cover its own length at the given speed.
The speed of the train is given as 54 km/h.
\[ \text{Speed} = 54 \text{ km/h} \times \frac{5}{18} \text{ m/s per km/h} \]\[ \text{Speed} = 3 \times 5 \text{ m/s} = 15 \text{ m/s} \]When a train crosses a platform, the total distance covered is the sum of the length of the train and the length of the platform.
Let \(L_T\) be the length of the train and \(L_P\) be the length of the platform.
Given: \(L_P = 90 \text{ m}\), Time \(t_1 = 60 \text{ s}\), Speed \(S = 15 \text{ m/s}\).
\[ \text{Distance} = L_T + L_P \]\[ \text{Distance} = \text{Speed} \times \text{Time} \]\[ L_T + 90 = 15 \text{ m/s} \times 60 \text{ s} \]\[ L_T + 90 = 900 \text{ m} \]\[ L_T = 900 - 90 \text{ m} \]\[ L_T = 810 \text{ m} \]When a train crosses an electric pole (or any point object), the distance covered is equal to the length of the train itself.
Let \(t_2\) be the time taken to cross the electric pole.
\[ \text{Distance} = L_T \]\[ \text{Time} = \frac{\text{Distance}}{\text{Speed}} \]\[ t_2 = \frac{810 \text{ m}}{15 \text{ m/s}} \]\[ t_2 = 54 \text{ s} \]B) 54 seconds is the correct answer. The train, being 810 m long, will take 54 seconds to cover its own length at a speed of 15 m/s, which is the time required to cross an electric pole.
The magnitude of the magnetic field due to a current-carrying circular coil varies with the number of turns n as ___.
The question asks how the magnitude of the magnetic field due to a current-carrying circular coil varies with the number of turns \(n\). We need to recall the formula for the magnetic field at the center of a circular coil and analyze its dependence on \(n\).
A) The magnetic field is directly proportional to the number of turns \(n\), as derived from the formula \(B_n = \frac{n \mu_0 I}{2R}\). Therefore, the magnitude of the magnetic field varies as \(n\).
To solve this problem, we need to apply the given rules to each letter in the word 'COMPARE'. We will identify each letter as either a consonant or a vowel, then change it according to the specified rule (following letter for consonants, preceding letter for vowels). Finally, we will examine the new group of letters to find which letters appear twice.
The new group of letters is D, N, N, Q, Z, S, D.
The letters D and N appear twice.
C) D and N
As determined in the step-by-step analysis, both 'D' and 'N' appear twice in the newly formed group of letters (D, N, N, Q, Z, S, D).