The problem requires us to evaluate a given mathematical expression after interchanging specific arithmetic operators. We need to replace '+' with '-' and '-' with '+', and similarly '×' with '÷' and '÷' with '×'. After performing these replacements, we will evaluate the new expression following the order of operations (BODMAS/PEMDAS).
A) -33 is the correct answer, as calculated by applying the operator interchanges and then following the order of operations.
The question asks about Mendeleev's Periodic Law. To answer this, one needs to recall the fundamental principle upon which Dmitri Mendeleev based his classification of elements.
A) The properties of elements are the periodic function of their atomic masses. Mendeleev's original Periodic Law stated that the physical and chemical properties of elements are a periodic function of their atomic masses. He arranged elements in increasing order of their atomic masses and observed that elements with similar properties recurred at regular intervals.
The question asks for an equivalent physical scenario when resistors are connected in parallel. We need to understand how resistance changes in a parallel combination and relate it to the physical properties of a conductor (length and cross-sectional area).
where \(\rho\) is the resistivity of the material, \(L\) is the length of the conductor, and \(A\) is its cross-sectional area.
This implies that connecting resistors in parallel decreases the overall resistance of the circuit.
A) Increasing cross-sectional area of the conductor: When the cross-sectional area of a conductor increases, its resistance decreases. This is analogous to connecting resistors in parallel, which also results in a decrease in the total equivalent resistance.
The problem involves decoding a pattern in a given code language. We need to identify the rule by which letters are transformed from the original word to the coded word and then apply the same rule to the target word.
The pattern observed is that each letter is shifted forward by 3 positions in the alphabet.
The pattern holds true: each letter is shifted forward by 3 positions.
Therefore, CLAN will be written as FODQ.
Correct Option: B) FODQ
The fraction equivalent to 0.474747... is:
\(\frac{47}{99}\)
\(\frac{11}{27}\)
\(\frac{27}{9}\)
\(\frac{27}{100}\)
The problem asks us to convert a repeating decimal into a fraction. We can solve this by setting the repeating decimal equal to a variable, multiplying by a power of 10 to shift the decimal, and then subtracting the original equation to eliminate the repeating part.
Correct Option: A) The fraction equivalent to \(0.474747...\) is \(\frac{47}{99}\).
The question asks to identify the type of chemical reaction involved in the formation of water from hydrogen and oxygen. We need to recall the definitions of different types of chemical reactions and match them with the given process.
A) Combination reaction — As explained above, two elements (hydrogen and oxygen) combine to form a single compound (water), which is the definition of a combination reaction.
The question asks to identify the biological process represented by the constantly dividing cells at the root apex. This points directly to the function of meristematic tissues in plants.
A) Meristematic growth — This term accurately describes the growth that occurs due to the activity of meristematic tissues, such as those found at the root apex, where cells are constantly dividing to increase the plant's length.
The question asks to identify the winner of the 75th edition of the Santosh Trophy, which took place in 2021-22. This requires knowledge of recent sports events, specifically the results of the Santosh Trophy football tournament.
Correct Option: B) Kerala won the Santosh Trophy 2021-22, defeating West Bengal in the final match held at the Manjeri Payyanad Stadium in Malappuram, Kerala. This was their seventh title.
The question asks to identify the type of vegetation based on a list of tree species: Safflower, Shisham, Khair, Arjun, and Mulberry. This requires knowledge of the characteristic tree species found in different forest types in India.
C) Tropical Deciduous Forests are characterized by trees like Shisham, Khair, Arjun, and Mulberry, which shed their leaves during the dry season. These forests are widespread in India.
To find the average score of the entire class, we need to calculate the total score of all students and then divide it by the total number of students. The total score can be found by summing the total scores of the two groups of students.
Total score of a group = Number of students in the group \(\times\) Average score of the group
\[ \text{Total Score}_1 = 12 \times 80 = 960 \]Average score of the class = Total score of the class / Total number of students in the class
\[ \text{Average Score}_{\text{Class}} = \frac{2310}{30} = 77 \]D) 77 is the correct average score for the entire class.