The question asks for the location where the 17th campus of the National Institute of Fashion Technology (NIFT) was inaugurated in July 2022. This is a factual question related to current affairs and general knowledge about national institutions.
Correct Option: C) Panchkula
Which of the following is the general formula of alkene?
CₙH₂ₙ₊₂
CₙH₂ₙ₊₄
Câ‚™Hâ‚‚â‚™
CₙH₂ₙ₋₂
The question asks for the general formula of an alkene. To answer this, we need to recall the definitions and general formulas for different types of hydrocarbons, specifically alkanes, alkenes, and alkynes.
C) CnH2n — This is the correct general formula for alkenes, where 'n' represents the number of carbon atoms.
The problem requires us to substitute the given operators with their interchanged counterparts and then evaluate the resulting expression following the order of operations (BODMAS/PEMDAS).
\[ 160 \times 8 - 22 \times 11 \div 180 \times 6 - 4 = ? \]
The original expression is: \[ 160 \times 8 - 22 \times 11 \div 180 \times 6 - 4 \] After interchanging the operators, it becomes: \[ 160 \div 8 + 22 \div 11 \times 180 \div 6 + 4 \]
First, perform divisions from left to right:
Substitute these values back into the expression:
\[ 20 + 2 \times 30 + 4 \]
Next, perform multiplication:
Substitute this value back into the expression:
\[ 20 + 60 + 4 \]
Finally, perform additions from left to right:
D) 84 is the correct answer, as derived from the step-by-step calculation.
The question asks to identify the person behind the Grameen Bank Model, which influenced the establishment of Regional Rural Banks (RRBs) in India. This requires knowledge of prominent figures in microfinance and rural development.
B) Muhammad Yunus is the founder of the Grameen Bank in Bangladesh, which pioneered the concept of microcredit – providing small loans to impoverished individuals without requiring collateral. This model has been globally recognized for its success in poverty alleviation and has inspired similar initiatives, including the establishment of Regional Rural Banks (RRBs) in India, which aim to provide credit and other banking facilities to small and marginal farmers, agricultural laborers, artisans, and small entrepreneurs in rural areas.
The question asks for the correct explanation of why metals are electropositive. Electropositivity is a chemical property related to an element's tendency to lose or gain electrons and form ions.
Correct Option: A) Metals lose electrons to form cations. This statement accurately describes the process by which metals exhibit electropositivity. When a metal atom loses one or more electrons, it forms a positively charged ion, known as a cation. For example, a sodium atom (\(\text{Na}\)) loses one electron to become a sodium ion (\(\text{Na}^{+}\)).
This problem involves calculating the original cost price of an item given its final selling price after multiple successive percentage gains. We need to work backward from the final selling price, reversing the effect of each 25% gain.
Let the cost price of the watch to the first seller be \(C_1\).
The first seller gains 25%. So, the selling price for the first seller (which is the cost price for the second seller, \(C_2\)) is:
\[ C_2 = C_1 \times \left(1 + \frac{25}{100}\right) = C_1 \times \left(1 + \frac{1}{4}\right) = C_1 \times \frac{5}{4} \]The second seller also gains 25%. So, the selling price for the second seller (which is the cost price for the third seller, \(C_3\)) is:
\[ C_3 = C_2 \times \left(1 + \frac{25}{100}\right) = C_2 \times \frac{5}{4} \]Substitute the expression for \(C_2\) from step 2 into the equation for \(C_3\):
\[ C_3 = \left(C_1 \times \frac{5}{4}\right) \times \frac{5}{4} = C_1 \times \left(\frac{5}{4}\right)^2 \]The third seller also gains 25%. The final selling price (SP) is Rs 1,250. So, the final selling price is:
\[ \text{SP} = C_3 \times \left(1 + \frac{25}{100}\right) = C_3 \times \frac{5}{4} \]Substitute the expression for \(C_3\) from step 4 into the equation for SP:
\[ \text{SP} = \left(C_1 \times \left(\frac{5}{4}\right)^2\right) \times \frac{5}{4} = C_1 \times \left(\frac{5}{4}\right)^3 \]We are given that the final selling price is Rs 1,250. So,
\[ 1250 = C_1 \times \left(\frac{5}{4}\right)^3 \]\[ 1250 = C_1 \times \frac{125}{64} \]Now, solve for \(C_1\):
\[ C_1 = 1250 \times \frac{64}{125} \]\[ C_1 = 10 \times 64 \]\[ C_1 = 640 \]A) The cost price of the watch to the first seller is Rs 640.
The area (in cm²) of a triangle, the lengths of whose sides are 5 cm, 7 cm, and 8 cm, is ____.
To find the area of a triangle when the lengths of its three sides are given, we use Heron's formula. Heron's formula requires calculating the semi-perimeter first.
Let the sides of the triangle be \(a\), \(b\), and \(c\).
The semi-perimeter is half the perimeter of the triangle.
\[ s = \frac{a + b + c}{2} \]\[ s = \frac{5 + 7 + 8}{2} \]\[ s = \frac{20}{2} \]\[ s = 10 \text{ cm} \]Heron's formula for the area of a triangle (\(A\)) is:
\[ A = \sqrt{s(s-a)(s-b)(s-c)} \]To simplify \(\sqrt{300}\), we look for perfect square factors.
\[ A = \sqrt{100 \times 3} \]\[ A = \sqrt{100} \times \sqrt{3} \]\[ A = 10\sqrt{3} \text{ cm}^2 \]D) \(10\sqrt{3}\) — The calculated area of the triangle using Heron's formula is \(10\sqrt{3} \text{ cm}^2\).
To solve this problem, we need to track Aakash's movements step-by-step, noting the distance and direction for each segment. We can visualize this as plotting points on a 2D coordinate system or simply drawing a path. The final position (Point Z) relative to the starting position (Point O) will determine the distance and direction needed to return to O.
Therefore, Aakash should drive 4 km towards the north to reach Point O from Point Z.
A) 4 km towards the north
To balance a chemical equation, the number of atoms of each element on the reactant side must be equal to the number of atoms of the same element on the product side. This adheres to the Law of Conservation of Mass. We will systematically balance each element, starting with the most complex compounds or elements that appear in only one reactant and one product.
Identify the unbalanced equation:
\( \text{Fe} + \text{H}_2\text{O} \rightarrow \text{Fe}_3\text{O}_4 + \text{H}_2 \)
Balance Iron (Fe) atoms:
There is 1 Fe atom on the reactant side and 3 Fe atoms on the product side (in \( \text{Fe}_3\text{O}_4 \)). To balance Fe, place a coefficient of 3 in front of Fe on the reactant side:
\( 3\text{Fe} + \text{H}_2\text{O} \rightarrow \text{Fe}_3\text{O}_4 + \text{H}_2 \)
Balance Oxygen (O) atoms:
There is 1 O atom on the reactant side (in \( \text{H}_2\text{O} \)) and 4 O atoms on the product side (in \( \text{Fe}_3\text{O}_4 \)). To balance O, place a coefficient of 4 in front of \( \text{H}_2\text{O} \) on the reactant side:
\( 3\text{Fe} + 4\text{H}_2\text{O} \rightarrow \text{Fe}_3\text{O}_4 + \text{H}_2 \)
Balance Hydrogen (H) atoms:
Now, count the H atoms. On the reactant side, there are \( 4 \times 2 = 8 \) H atoms (in \( 4\text{H}_2\text{O} \)). On the product side, there are 2 H atoms (in \( \text{H}_2 \)). To balance H, place a coefficient of 4 in front of \( \text{H}_2 \) on the product side:
\( 3\text{Fe} + 4\text{H}_2\text{O} \rightarrow \text{Fe}_3\text{O}_4 + 4\text{H}_2 \)
Verify the balanced equation:
All atoms are balanced.
Correct Option: D) 3Fe(s) + 4H₂O(g) → Fe₃O₄(s) + 4H₂(g)
The question asks to identify the personality widely remembered for hoisting the Indian National Flag at Gowalia Tank Maidan during the Quit India Movement in 1942. This requires knowledge of key figures and events of the Indian independence movement, specifically the Quit India Movement.
Correct Option: A) Aruna Asaf Ali is widely remembered for hoisting the Indian National Flag at the Gowalia Tank Maidan in Bombay on August 9, 1942, marking the beginning of the Quit India Movement. This act of defiance occurred after most of the prominent leaders, including Mahatma Gandhi, were arrested, making her a national hero.