The question asks to identify the Five-Year Plan in India where the removal of poverty was the primary objective. This requires knowledge of the objectives and focus areas of different Five-Year Plans.
A) Sixth - The Sixth Five-Year Plan (1980-1985) had "removal of poverty" (Garibi Hatao) and "technological self-reliance" as its foremost objectives. This plan focused on strengthening the infrastructure, agriculture, and industrial sectors to achieve these goals.
To find the marked price, we first need to calculate the selling price using the given cost price and profit percentage. Then, using the selling price and the discount percentage, we can determine the marked price.
The cost price (CP) is âš480, and the profit is 10%.
\[ \text{Profit} = 10\% \text{ of CP} = 0.10 \times 480 = \text{âš}48 \]\[ \text{Selling Price (SP)} = \text{CP} + \text{Profit} = 480 + 48 = \text{âš}528 \]The shopkeeper sells the shoes at a discount of 34% on the marked price. This means the selling price is 100% - 34% = 66% of the marked price.
\[ \text{SP} = (100\% - \text{Discount}\% ) \times \text{MP} \]\[ 528 = (100\% - 34\%) \times \text{MP} \]\[ 528 = 66\% \times \text{MP} \]\[ 528 = 0.66 \times \text{MP} \]\[ \text{MP} = \frac{528}{0.66} \]\[ \text{MP} = \text{âš}800 \]C) âš800 is the correct marked price. This is derived by first calculating the selling price from the cost price and profit, and then using the selling price and discount percentage to find the marked price.
This problem involves setting up and solving a system of linear equations based on the given age relationships at two different points in time: 16 years ago and the present. We will use variables to represent the current ages of the father and son and then translate the given conditions into algebraic equations.
Define variables for present ages:
Let the present age of the father be \(F\) years.
Let the present age of the son be \(S\) years.
Formulate equations based on the given conditions:
Condition 1: 16 years ago
16 years ago, the father's age was \(F - 16\).
16 years ago, the son's age was \(S - 16\).
According to the problem, 16 years ago, the father's age was 4 times the age of his son:
\[ F - 16 = 4(S - 16) \]\[ F - 16 = 4S - 64 \]\[ F = 4S - 64 + 16 \]\[ F = 4S - 48 \quad \text{(Equation 1)} \]Condition 2: Present ages
Now, the father is twice as old as his son:
\[ F = 2S \quad \text{(Equation 2)} \]Solve the system of equations:
We have two equations:
1) \(F = 4S - 48\)
2) \(F = 2S\)
Substitute Equation 2 into Equation 1:
\[ 2S = 4S - 48 \]\[ 48 = 4S - 2S \]\[ 48 = 2S \]\[ S = \frac{48}{2} \]\[ S = 24 \]Calculate the father's present age:
Substitute the value of \(S\) back into Equation 2:
\[ F = 2S \]\[ F = 2(24) \]\[ F = 48 \]Find the difference between their present ages:
Difference \( = F - S \)
\[ \text{Difference} = 48 - 24 \]\[ \text{Difference} = 24 \]D) 24 years
If ‘×’ means ‘÷’, ‘÷’ means ‘+’, ‘+’ means ‘−’, and ‘−’ means ‘×’, what will come in place of the question mark (?) in the following equation?
2 − (684 + 228 × 19) × 21 ÷ 4 =?
This problem involves substituting given symbol transformations into a mathematical expression and then evaluating the expression using the BODMAS/PEMDAS rule (Brackets/Parentheses, Orders/Exponents, Division, Multiplication, Addition, Subtraction).
First, solve the operations inside the parenthesis.
Inside the parenthesis: \(684 - 228 \div 19\)
Perform division first:
\[ 228 \div 19 = 12 \]Now, perform subtraction:
\[ 684 - 12 = 672 \]Substitute this back into the equation:
\[ 2 \times 672 \div 21 + 4 = ? \]Next, perform multiplication and division from left to right.
Perform multiplication:
\[ 2 \times 672 = 1344 \]Now, perform division:
\[ 1344 \div 21 = 64 \]Finally, perform addition:
\[ 64 + 4 = 68 \]Thus, the value of the expression is 68.
B) 68
The given series consists of letter-clusters followed by numbers. We need to identify the pattern in both the letters and the numbers separately to find the next term in the series.
Correct Option: B) MRX 29
The problem presents a proportion involving algebraic expressions. We need to find an expression equivalent to 'z' by using the property of proportions that the product of the means equals the product of the extremes.
The given proportion is \(2xy^2 : 2x^2y :: 2x^2y : z\).
This can be written in fraction form as:
\[ \frac{2xy^2}{2x^2y} = \frac{2x^2y}{z} \]To solve for \(z\), we can cross-multiply:
\[ (2xy^2) \times z = (2x^2y) \times (2x^2y) \]Simplify the right side of the equation:
\[ 2xy^2 \cdot z = 4x^4y^2 \]Now, isolate \(z\) by dividing both sides by \(2xy^2\):
\[ z = \frac{4x^4y^2}{2xy^2} \]Perform the division:
Combine these results to find \(z\):
\[ z = 2x^3 \]A) \(2x^3\) is the correct expression for \(z\), as derived from the proportion.
This question tests the basic understanding of image formation by a concave mirror, specifically when the object is placed at infinity. We need to recall the rules of ray optics for concave mirrors.
Correct Option: D) focus
This question tests the understanding of how a concave mirror reflects a parallel beam of light that is not parallel to its principal axis. We need to recall the properties of reflection from a concave mirror, specifically concerning parallel rays.
Correct Option: A) principal focal plane. When a parallel beam of light is incident on a concave mirror and is not parallel to the principal axis, all the rays in that beam converge at a point in the focal plane. This plane is perpendicular to the principal axis and passes through the principal focus. The point of convergence will be on this plane, but not necessarily at the principal focus itself, as the beam is off-axis.
This question asks for the standard unit of electrical resistance. To answer this, we need to recall the fundamental units for various electrical quantities.
Correct Option: C) Ohm â The Ohm is the SI derived unit of electrical resistance, named after German physicist Georg Simon Ohm. It is defined as a volt per ampere (\(V/A\)).