Which of the following can be expressed in the form of a standard quadratic equation?
(2x − 1)³ = x² − 3x + 2
\(\sqrt{2x^{2}+3x-4}\) − 2x + 5 = 0
(x + 1)(x + 2) = x² − 16
(2x + 3)² + 4x − 5 = (2x + 1)(2x − 3)
A standard quadratic equation is an equation that can be written in the form \(ax^2 + bx + c = 0\), where \(a\), \(b\), and \(c\) are real numbers and \(a \neq 0\). We need to examine each given option and simplify it to see if it fits this standard form.
B) \(\sqrt{2x^2 + 3x - 4} - 2x + 5 = 0\) can be simplified to \(2x^2 - 23x + 29 = 0\), which is in the standard quadratic form \(ax^2 + bx + c = 0\).
The problem presents a number series, and we need to find the pattern to determine the next number. We will analyze the differences between consecutive terms to identify a mathematical relationship.
D) 306 is the correct answer, as derived from the established pattern.
The value of \(\frac{\sin16^\circ}{\cos74^\circ}+\frac{\tan14^\circ}{\cot76^\circ}\) is:
To solve this problem, we need to use the complementary angle identities in trigonometry. Specifically, we will use the identities: \(\sin(90^\circ - \theta) = \cos\theta\) and \(\tan(90^\circ - \theta) = \cot\theta\).
Correct Option: A) 2
The question asks for the valency of group 17 elements. Valency is the combining capacity of an element, determined by the number of electrons an atom needs to gain, lose, or share to achieve a stable electron configuration (usually an octet, meaning 8 electrons in the outermost shell, or a duplet for hydrogen and helium).
Correct Option: A) 1 is correct because group 17 elements (halogens) have 7 valence electrons and need to gain 1 electron to complete their octet, thus having a valency of 1.
To find the actual time from a mirror image time on a 12-hour clock, we use a simple rule: subtract the given mirror time from 11:60 (which is equivalent to 12:00). This method accounts for both hours and minutes correctly.
Correct Option: C) 6:20
The question asks to identify the first 'Made in India' Petascale Supercomputer installed at IIT Roorkee under the National Supercomputing Mission (NSM) in 2022. This requires knowledge of specific supercomputer installations under India's NSM program.
Correct Option: C) PARAM Ganga is the first 'Made in India' Petascale Supercomputer installed at IIT Roorkee under the National Supercomputing Mission (NSM) in 2022. It has a supercomputing capacity of 1.66 Petaflops.
When two objects move in the same direction, their relative speed is the difference between their individual speeds. The total distance covered for one train to cross another is the sum of their lengths. We will use the formula: \(\text{Distance} = \text{Speed} \times \text{Time}\).
The speeds are given in km/h, and the time is in seconds. To maintain consistent units, we convert km/h to m/s by multiplying by \(\frac{5}{18}\).
Speed of faster engine \(S_1 = 36 \text{ km/h}\)
\[ S_1 = 36 \times \frac{5}{18} \text{ m/s} = 2 \times 5 \text{ m/s} = 10 \text{ m/s} \]Speed of slower engine \(S_2 = 18 \text{ km/h}\)
\[ S_2 = 18 \times \frac{5}{18} \text{ m/s} = 5 \text{ m/s} \]Since both engines are running in the same direction, their relative speed is the difference between their speeds.
\[ \text{Relative Speed} = S_1 - S_2 = 10 \text{ m/s} - 5 \text{ m/s} = 5 \text{ m/s} \]Let the length of each engine be \(L\) meters. When the faster engine crosses the slower one, the total distance covered is the sum of their lengths.
\[ \text{Total Distance} = L + L = 2L \text{ meters} \]We know that \(\text{Distance} = \text{Speed} \times \text{Time}\). The time taken to cross is 8 seconds.
\[ 2L = \text{Relative Speed} \times \text{Time} \]\[ 2L = 5 \text{ m/s} \times 8 \text{ s} \]\[ 2L = 40 \text{ m} \]Now, solve for \(L\).
\[ L = \frac{40}{2} \text{ m} = 20 \text{ m} \]B) The length of each train engine is 20 m.
Which of the following is reducible to a quadratic equation?
A.) (m + 1) − \( \frac{1}{m+1} \) = 65
B.) x³ + 3x = 2x³ − 4x²
C.) (a + b)² = \( \frac{3}{b} \)
D.) x + (3x − 2) = \( \frac{1}{x^2} \) − 6
A quadratic equation is an equation of the form \(ax^2 + bx + c = 0\), where \(a \neq 0\). To determine which of the given options is reducible to a quadratic equation, we need to simplify each equation and check if it can be expressed in this standard form.
A) The equation \( (m + 1) - \frac{1}{m+1} = 65 \) can be transformed into \( y^2 - 65y - 1 = 0 \) by substituting \(y = m+1\). This is a standard quadratic equation of the form \(ay^2 + by + c = 0\).
The problem asks us to identify the letter-cluster pair that follows the same logical relationship as the given pairs: MON : PLQ and KIT : NFW. We need to find the pattern of letter shifts between the first and second clusters in the given examples and then apply that pattern to the options.
C) PEN : SBQ
This pair follows the \((+3, -3, +3)\) logic.