In this question, a group of numbers/symbols is coded using letters as per the table given below and the conditions which follow. The correct combination of codes following the conditions is your answer.
| Number/Symbol | $ | 3 | @ | 8 | % | 2 | # | & | 6 | φ | π | 7 | 5 | Ñ„ |
| Code | A | V | L | K | R | M | B | F | N | T | E | C | S | W |
Conditions:
(i) If the first element is a symbol and the last element is a number, the codes for these two (the first and the last elements) are to be interchanged.
(ii) If the first element is an odd number and the last element is an even number, the first and last elements are to be coded as ©.
(iii) If both second and fourth elements are multiples of 3, both second and fourth elements are to be coded as the code for the second element.
#376Ï•%
In the given reaction which substance undergoes oxidation?
2Cu + O2 → 2CuO
Copper oxide
Only copper
Copper and oxygen
Only oxygen
Find the median of the frequency distribution given below.
| Marks | Frequency |
| 30 | 4 |
| 40 | 7 |
| 50 | 2 |
| 85 | 6 |
In â–³ABC, m(\(\overline{AB}\)) = m(\(\overline{AC}\)), and m∠BAC = 30°. If the side BC of â–³ABC is extended to D, then find m∠ACD.