The mean proportional between
8 + 4\(\sqrt{2}\) and 6 -3\(\sqrt{2}\) is
Find the value of \(\frac{\mathrm{tan}^{2}60^\circ+\mathrm{cot}^{2}30^\circ}{\mathrm{tan}^{2}20^\circ-\mathrm{sec}^{2}20^\circ}-\frac{\mathrm{sin}90^\circ+\mathrm{cos}0^\circ}{\mathrm{cosec}^{2}20^\circ-\mathrm{cot}^{2}20^\circ}\)