The question asks to identify the athlete who set a new men's 35 km race walk national record at the Indian Open Race Walking Competition 2022 with a specific time. This requires knowledge of recent national sports records and achievements.
In the Indian Open Race Walking Competition 2022, Juned Khan set a new national record in the men's 35 km race walk with a time of 2:40:16.
D) Juned Khan — Juned Khan indeed clocked 2:40:16 to set a new men's 35 km race walk national record at the Indian Open Race Walking Competition 2022, thereby qualifying for the World Athletics Championships in Oregon.
If the area of a triangle whose base measures 3 cm is 4 cm², then its corresponding height is:
4\( \frac{1}{3} \) cm
3\( \frac{2}{3} \) cm
2\( \frac{2}{3} \) cm
1\( \frac{2}{3} \) cm
To find the corresponding height of a triangle given its area and base, we use the standard formula for the area of a triangle: \[\text{Area} = \frac{1}{2} \times \text{base} \times \text{height}\]. We will rearrange this formula to solve for the height.
Identify the given values:
Recall the formula for the area of a triangle:
\[ \text{Area} = \frac{1}{2} \times \text{base} \times \text{height} \]
Substitute the given values into the formula:
\[ 4 = \frac{1}{2} \times 3 \times \text{height} \]
Simplify the equation:
\[ 4 = \frac{3}{2} \times \text{height} \]
Solve for the height:
To isolate 'height', multiply both sides of the equation by \( \frac{2}{3} \):
\[ \text{height} = 4 \times \frac{2}{3} \]
\[ \text{height} = \frac{8}{3} \text{ cm} \]
Convert the improper fraction to a mixed number:
\[ \frac{8}{3} = 2 \frac{2}{3} \text{ cm} \]
C) The calculated height is \( 2 \frac{2}{3} \text{ cm} \), which matches option C.
The question asks to identify the compound with the lowest boiling point among a homologous series. In a homologous series, the boiling point generally increases with an increase in the number of carbon atoms (and thus molecular mass) due to stronger van der Waals forces.
CH₄O (Methanol) has the lowest number of carbon atoms (1) among the given options. Therefore, it has the lowest molecular mass and the weakest intermolecular forces, resulting in the lowest boiling point.
The question asks to identify the state government that implemented the Kalyana Lakshmi and Shaadi Mubarak Schemes as of July 2022. This requires knowledge of specific welfare schemes and the states associated with them.
A) Telangana — The Telangana government launched the Kalyana Lakshmi Scheme for Hindu brides and the Shaadi Mubarak Scheme for Muslim brides in October 2014. These schemes provide financial assistance to eligible unmarried girls from economically backward families at the time of their marriage.
This is a coding-decoding problem where we need to find the codes for specific words by comparing the given coded sentences. We will identify common words and their corresponding codes across the sentences to deduce the code for each word.
D) tq, ae — As derived in the step-by-step explanation, the code for 'kind' is 'tq' and the code for 'you' is 'ae'. Combining these gives 'tq, ae'.
The question asks to identify the Indian space mission orbiter that carried the Large Area Soft X-ray Spectrometer (CLASS) payload, which detected a solar proton event in January 2022. This requires knowledge of the payloads associated with India's major planetary missions.
The Large Area Soft X-ray Spectrometer (CLASS) is a payload on India's second lunar mission, Chandrayaan-2. It is designed to measure the X-ray spectrum of the Moon, which helps in understanding its elemental composition. In January 2022, CLASS detected a significant solar proton event, which was a notable scientific observation. Chandrayaan-2 was launched in 2019 and its orbiter is still operational.
B) Chandrayaan-2. The Large Area Soft X-ray Spectrometer (CLASS) is indeed a payload on the Chandrayaan-2 orbiter. It successfully detected a solar proton event in January 2022, as reported by ISRO.
A person who spends 36\( \frac{2}{3} \)% of his monthly income is able to save Rs 5,700 per month. His monthly expenses are:
The problem provides the percentage of income spent and the amount saved. We need to find the monthly expenses. We can determine the percentage of income saved, then use the given savings amount to find the total monthly income. Once the total income is known, we can calculate the monthly expenses.
The person spends \(36\frac{2}{3}\)\% of his monthly income.
\[ 36\frac{2}{3}\% = \left(36 + \frac{2}{3}\right)\% = \left(\frac{36 \times 3 + 2}{3}\right)\% = \left(\frac{108 + 2}{3}\right)\% = \frac{110}{3}\% \]To convert this percentage to a fraction, divide by 100:
\[ \frac{110}{3}\% = \frac{110}{3 \times 100} = \frac{110}{300} = \frac{11}{30} \]So, the person spends \(\frac{11}{30}\) of his income.
If spending is \(\frac{11}{30}\) of the income, then savings will be the remaining portion of the income (which is 1 or 100%).
\[ \text{Fraction of income saved} = 1 - \text{Fraction of income spent} \] \[ \text{Fraction of income saved} = 1 - \frac{11}{30} = \frac{30 - 11}{30} = \frac{19}{30} \]We are given that the monthly savings are Rs 5,700. We know that savings represent \(\frac{19}{30}\) of the total income.
Let the total monthly income be \(I\).
\[ \frac{19}{30} \times I = 5700 \] \[ I = \frac{5700 \times 30}{19} \]Since \(57 = 19 \times 3\), we have \(5700 = 19 \times 300\).
\[ I = \frac{19 \times 300 \times 30}{19} \] \[ I = 300 \times 30 = 9000 \]So, the total monthly income is Rs 9,000.
Monthly expenses can be calculated in two ways:
Method 1: Income - Savings
\[ \text{Expenses} = \text{Income} - \text{Savings} \] \[ \text{Expenses} = 9000 - 5700 = 3300 \]Method 2: Percentage of Income Spent
\[ \text{Expenses} = \frac{11}{30} \times \text{Income} \] \[ \text{Expenses} = \frac{11}{30} \times 9000 \] \[ \text{Expenses} = 11 \times \frac{9000}{30} \] \[ \text{Expenses} = 11 \times 300 = 3300 \]Thus, the monthly expenses are Rs 3,300.
Correct Option: B) 3,300
The question asks about the chemical composition of Plaster of Paris (PoP), specifically the ratio of calcium sulfate formula units to water molecules. To answer this, we need to recall the chemical formula of Plaster of Paris.
D) two formula units of CaSO₄ share one molecule of water
The chemical formula of Plaster of Paris is \( \text{CaSO}_4 \cdot \frac{1}{2}\text{H}_2\text{O} \). This means that one formula unit of calcium sulfate is associated with half a molecule of water. To express this in terms of whole numbers, we can say that two formula units of \(\text{CaSO}_4\) share one molecule of \(\text{H}_2\text{O}\). This is represented as \( (2\text{CaSO}_4) \cdot \text{H}_2\text{O} \).
The question asks to identify a chemical compound commonly used in the manufacture of cement. Cement is a binding material, and its primary components are calcium-based compounds.
B) CaO (Calcium oxide) is a primary component and is crucial in the manufacture of cement. It is formed from the calcination of limestone and is the main ingredient in cement clinker.
This is a logical reasoning problem involving ordering people based on the years they travelled. We need to deduce the travel year for each person using the given clues and then identify who travelled in 2014.
| Year | Person |
|---|---|
| 2010 | |
| 2012 | |
| 2014 | |
| 2016 | |
| 2018 | C |
| 2020 |
| Year | Person |
|---|---|
| 2010 | |
| 2012 | D |
| 2014 | |
| 2016 | |
| 2018 | C |
| 2020 | A |
| Year | Person |
|---|---|
| 2010 | F |
| 2012 | D |
| 2014 | E |
| 2016 | |
| 2018 | C |
| 2020 | A |
| Year | Person |
|---|---|
| 2010 | F |
| 2012 | D |
| 2014 | E |
| 2016 | B |
| 2018 | C |
| 2020 | A |
Correct Option: C) E travelled in 2014.