The question asks about the main products of a neutralisation reaction. A neutralisation reaction is a fundamental chemical reaction between an acid and a base. Understanding the general equation for this reaction will help identify the products.
Correct Option: B) \(H_2O\) and salt
If the curved surface area of a right circular cylinder is 880 cm² and the diameter of its base is 7 cm, then the height (in cm) of the cylinder is ______.
Take π = \( \frac{22}{7} \)
The problem asks us to find the height of a right circular cylinder given its curved surface area and the diameter of its base. We will use the formula for the curved surface area of a cylinder and the given values to solve for the height.
The radius (\(r\)) is half of the diameter.
\[ r = \frac{\text{Diameter}}{2} = \frac{7 \text{ cm}}{2} \]The curved surface area (CSA) of a cylinder is given by:
\[ \text{CSA} = 2 \pi r h \]where \(r\) is the radius of the base and \(h\) is the height of the cylinder.We have \(\text{CSA} = 880 \text{ cm}^2\), \(r = \frac{7}{2} \text{ cm}\), and \( \pi = \frac{22}{7} \). We need to find \(h\).
\[ 880 = 2 \times \frac{22}{7} \times \frac{7}{2} \times h \]Simplify the equation:
\[ 880 = \left( 2 \times \frac{22}{7} \times \frac{7}{2} \right) \times h \]The terms \(2\) and \(\frac{1}{2}\) cancel out, and the terms \(7\) and \(\frac{1}{7}\) cancel out:\[ 880 = 22 \times h \]Now, divide both sides by 22 to find \(h\):\[ h = \frac{880}{22} \]\[ h = 40 \text{ cm} \]Correct Option: A) 40
The height of the cylinder is 40 cm.
A neutralisation reaction is fundamentally a reaction between an acid and a base, typically producing a salt and water. We need to examine each given reaction to determine if it fits this definition. We will identify the reactants as acid, base, or neither, and then check if the products are salt and water.
Based on the analysis, only reaction A does not fit the definition of a neutralisation reaction.
Correct Option: A) The reaction \( \text{CaO} + \text{H}_2\text{O} \rightarrow \text{Ca(OH)}_2 \) is a combination reaction where a basic oxide reacts with water to form a base. It does not involve an acid and a base reacting to form a salt and water, hence it is not a neutralisation reaction.
In this question, a group of numbers/symbols is coded using letters as per the table given below and the conditions which follow. The correct combination of codes following the conditions is your answer.
| Number/symbol | * | 2 | @ | 5 | ^ | + | 7 | # | % | 9 | 4 |
| Letter code | J | P | A | F | D | N | R | K | M | Z | B |
Conditions:
(i) If both the first and fourth elements are even numbers, the codes for these two are to be interchanged.
(ii) If both second and third elements are perfect squares, the third element is to be coded as the code for the second element.
Which one of the following would be the code for % 9 4 # 2?
The problem requires us to code a given sequence of numbers/symbols based on a provided table and two specific conditions. We need to first find the direct codes for each element, then apply the conditions in the given order to determine the final code.
A) MZZKP is the correct code after applying the conditions.
If ‘+’ means ‘−’, ‘−’ means ‘×’, ‘×’ means ‘÷’, and ‘÷’ means ‘+’, what will come in place of the question mark (?) in the following equation?
17 ÷ 3 − 2 + 12 × 4 =?
The problem requires us to substitute the given new meanings for the mathematical operators into the expression and then evaluate the expression following the order of operations (BODMAS/PEMDAS).
Replacing each original operator with its new meaning:
The expression becomes:
\[ 17 + 3 \times 2 - 12 \div 4 = ? \]BODMAS/PEMDAS stands for Brackets/Parentheses, Orders/Exponents, Division and Multiplication (from left to right), Addition and Subtraction (from left to right).
The expression is now:
\[ 17 + 3 \times 2 - 3 \]The expression is now:
\[ 17 + 6 - 3 \]C) 20 is the correct answer, as derived from substituting the operators and following the order of operations.
The problem describes the relative positions of five runners (K, L, M, N, P) in a straight row. We need to deduce the exact arrangement of the runners based on the given clues and then identify the runner immediately to the left of P.
Identify the total number of positions: There are five runners, so there are five positions in the row.
Place K and M: "Runner K is standing at the first position and M is at the end position."
Row: K _ _ _ M
Place L, N, and M based on immediate left/right: "L is standing to the immediate left of N, and N is standing to the immediate left of M."
This means the sequence L-N-M is together. Since M is at the end, N must be in the 4th position and L in the 3rd position.
Row: K _ L N M
Place P: "P is standing third to the left of M."
Counting three positions to the left from M (which is at position 5):
Position 5: M
Position 4: N (1st to the left of M)
Position 3: L (2nd to the left of M)
Position 2: P (3rd to the left of M)
So, P is at the 2nd position.
Final arrangement: Combining all the information, the row is:
Position 1: K
Position 2: P
Position 3: L
Position 4: N
Position 5: M
The final arrangement is K P L N M.
Answer the question: "Who is standing to the immediate left of P?"
Looking at the final arrangement (K P L N M), the runner immediately to the left of P is K.
A) K — Based on the step-by-step deduction, K is in the first position and P is in the second, making K immediately to the left of P.
To solve this problem, we need to use the divisibility rule for 11. The rule states that a number is divisible by 11 if the difference between the sum of its digits at odd places (from the right) and the sum of its digits at even places (from the right) is either 0 or a multiple of 11.
Correct Option: A) 6
The question asks about the extension period of the Pradhan Mantri Garib Kalyan Anna Yojana (PMGKAY) as announced in March 2022. To answer this, one needs to recall the specific government announcement regarding the scheme's extension at that time.
Correct Option: D) September 2022
The question asks about the implementation year of the Integrated Wastelands Development Programme (IWDP) in India. This is a factual question related to government schemes and their historical timelines, which is a common topic in Indian competitive exams.
Correct Option: A) 1989–90
The Integrated Wastelands Development Programme (IWDP) was indeed launched in India during the financial year 1989–90. Its primary aim was to develop non-forest degraded lands and wastelands on a watershed basis, promoting sustainable land use and increasing productivity.
The problem presents a series of number pairs and asks us to find the missing number in the last pair based on the relationship observed in the previous pairs. We need to identify a mathematical pattern or rule that connects the first number to the second number in each given pair.
D) 3 is the correct answer because it follows the established pattern where the first number is \(n^3 + 1\) and the second number is \(n-1\).