Consider two circuits, A and B, each of which has six resistors and each circuit of resistance RA​ and RB respectively. In each circuit, the resistors are in such a way that the net resistance of each circuit is the minimum. Now a 20 V battery with negligible internal resistance is connected across each circuit separately, and the current drawn by circuit A and circuit B are equal. Then RA and RB will be:
RA​=15 Ω and RB=20 Ω
RA​=20 Ω and RB=15 Ω
RA​​=30 Ω and RB=15 Ω
RA​=15 Ω and RB=30 Ω
The number 0.\(\overline{335}\) can be represented in the form of \( \frac{p}{q} \)
(where P and Q are natural numbers) as:
\(\frac{332}{895}\)
\(\frac{332}{990}\)
\(\frac{332}{995}\)
\(\frac{332}{980}\)