The question asks to identify the organization that collaborated with NABARD to launch the 'Adavi' brand for marketing forest produce from Nilambur tribespeople. This is a factual question related to rural development and tribal welfare initiatives.
Correct Option: A) Jan Shikshan Sansthan
NABARD (National Bank for Agriculture and Rural Development) and Jan Shikshan Sansthan (JSS) have jointly launched the 'Adavi' brand. This initiative aims to market the forest produce harvested by the tribal communities in Nilambur, Kerala. Jan Shikshan Sansthans are institutions that provide vocational training and skill development to non-literates, neo-literates, and school dropouts, particularly in rural and tribal areas, thereby empowering them for livelihood generation.
To find the median of the data, we will use the empirical relationship between mean, median, and mode for a moderately skewed distribution. The formula states that \(\text{Mode} \approx 3 \times \text{Median} - 2 \times \text{Mean}\).
Given mean \( = 58.7 \)
Given mode \( = 61.1 \)
The empirical formula relating mean, median, and mode for a moderately skewed distribution is:
\[ \text{Mode} = 3 \times \text{Median} - 2 \times \text{Mean} \]Let the median be \( M \).
\[ 61.1 = 3M - 2(58.7) \]Add \( 117.4 \) to both sides of the equation:
\[ 61.1 + 117.4 = 3M \]\[ 178.5 = 3M \]Divide both sides by \( 3 \):
\[ M = \frac{178.5}{3} \]\[ M = 59.5 \]A) 59.5 is the correct median calculated using the empirical formula.
The question asks about the relationship between the magnetic field strength around a current-carrying conductor and the distance from the conductor. This can be understood by recalling Ampere's Law or the Biot-Savart Law for a straight current-carrying wire.
Where:
Correct Option: A) decreases with increase in distance
This problem involves working backward from the final selling price to find the original marked price. We need to account for VAT and discount percentages step-by-step.
D) The value of x is Rs 480. This is obtained by first removing the VAT from the final selling price to get the discounted price, and then using the discount percentage to find the original marked price.
In a certain code language, ‘GAURD’ is written as ‘LDYTE’ and ‘CLOVE’ is written as ‘HOSXF’. How will ‘HORSE’ be written in that language?
The problem is a coding-decoding question. We need to identify the pattern or rule used to transform the given words and then apply that rule to the target word.
The question asks to identify the narrow channel of sea that separates Sri Lanka from India. This is a geographical fact commonly tested in competitive exams.
A) Palk Strait — The Palk Strait is indeed the narrow channel of sea that separates the Indian state of Tamil Nadu from the Jaffna District of Sri Lanka. It connects the Bay of Bengal in the northeast with the Palk Bay and then the Gulf of Mannar in the southwest.
We need to find the percentage by which the marked price is above the cost price. We are given the trade discount, cash discount, and the net gain percentage. We can assume a cost price (e.g., 100 units) and then work forward to find the selling price, and then backward from the selling price to find the marked price, considering the discounts.
Let the Cost Price (\(\text{CP}\)) of the goods be \(\text{Rs. } 100\).
The retailer makes a net gain of 17.3% of the cost price.
\[ \text{Gain} = 17.3\% \text{ of CP} = 0.173 \times 100 = \text{Rs. } 17.3 \]\[ \text{Selling Price (SP)} = \text{CP} + \text{Gain} = 100 + 17.3 = \text{Rs. } 117.3 \]The retailer gives a trade discount of 25% followed by a cash discount of 8% on the already discounted price.
Let the Marked Price (\(\text{MP}\)) be \(\text{Rs. } x\).
After a trade discount of 25%, the price becomes:
\[ \text{Price after Trade Discount} = \text{MP} \times \left(1 - \frac{25}{100}\right) = x \times 0.75 = 0.75x \]A cash discount of 8% is given on this discounted price.
\[ \text{SP} = (\text{Price after Trade Discount}) \times \left(1 - \frac{8}{100}\right) \]\[ \text{SP} = 0.75x \times 0.92 \]We know \(\text{SP} = \text{Rs. } 117.3\).
\[ 117.3 = 0.75x \times 0.92 \]\[ 117.3 = 0.69x \]\[ x = \frac{117.3}{0.69} \]\[ x = 170 \]The Marked Price (\(\text{MP}\)) is \(\text{Rs. } 170\).
The Cost Price (\(\text{CP}\)) is \(\text{Rs. } 100\).
Difference between MP and CP \(= 170 - 100 = \text{Rs. } 70\).
Percentage above CP \[= \frac{\text{Difference}}{\text{CP}} \times 100\%\]
\[ = \frac{70}{100} \times 100\% = 70\% \]C) 70% is the correct answer. The marked price is fixed 70% above the cost price.
The question asks for the year in which Tamil was declared a classical language of India. This is a factual question related to Indian cultural policy and history. We need to recall the specific year of this declaration.
Correct Option: C) 2004 is the correct year when the Tamil language was declared as a classical language of India by the Government of India.
The problem asks us to identify a set of numbers that follows the same relationship as the given sets: (14, 98) and (22, 242). We need to find a mathematical operation or pattern connecting the two numbers in each given set and then apply that pattern to the options.
Let the first number be \(x\) and the second number be \(y\).
We need to find a relationship between 14 and 98. Let's try multiplication or division.
\[ 98 \div 14 = 7 \]So, \(y = 7 \times x\).
Alternatively, we can express 7 in terms of \(x\). If \(x = 14\), then \(7 = \frac{14}{2}\). So the relationship could be:
\[ y = x \times \frac{x}{2} = \frac{x^2}{2} \]Let's check this with the first set:
\[ \frac{14^2}{2} = \frac{196}{2} = 98 \]This relationship holds true for the first set.
Let's check if the same relationship \(y = \frac{x^2}{2}\) holds for the second set (22, 242).
Here, \(x = 22\).
\[ \frac{22^2}{2} = \frac{484}{2} = 242 \]This relationship also holds true for the second set. Therefore, the established pattern is that the second number is half the square of the first number.
We need to find an option \((x, y)\) where \(y = \frac{x^2}{2}\).
C) 6, 18
This question involves analyzing a set of inequalities and equalities to determine which of the given conclusions logically follows from the statement. We need to combine the given relations and check each conclusion individually.
The given statement is: \(E = R = S \le T \quad O = Z\)
Let's break down the statement into individual relations:
From (1) and (2), we can infer \(E = R = S\).
Now let's evaluate each conclusion:
From the combined statement, we have \(E = S\). If \(E = S\), then it is also true that \(E \ge S\) (since equality implies greater than or equal to). Therefore, this conclusion is true.
We know \(E = S\) and \(S \le T\). This means \(E \le T\). The relation \(E \le T\) implies that \(T\) can be greater than \(E\) or equal to \(E\). It does not necessarily mean \(T > E\). For example, if \(E=5\) and \(S=5\) and \(T=5\), then \(E \le T\) is true, but \(T > E\) is false. Therefore, this conclusion is not necessarily true.
The statement does not provide any information about 'N'. Therefore, we cannot establish any relationship between \(R\) and \(N\). This conclusion is false.
We know \(S \le T\) and \(O = Z\). There is no direct or indirect relation given between \(T\) and \(Z\) (or \(O\)). Therefore, we cannot establish any relationship between \(T\) and \(Z\). This conclusion is false.
B) 1 is the correct option because Conclusion 1 (\(E \ge S\)) is true based on the given statement \(E = S\).