The question asks about the primary use of yeast in food and beverage production. This requires knowledge of common microbial applications in biotechnology, specifically fermentation processes.
Correct Option: A) Yeast is famously used in the production of alcoholic beverages like wine and beer. In wine making, yeast ferments the sugars present in grape juice into ethanol and carbon dioxide.
The speed of light in two transparent media A and B are 2 × 108 m/sec and 2.25 × 108 m/sec. The refractive index of medium A with respect to medium B is equal to:
The problem asks us to calculate the refractive index of medium A with respect to medium B. We are given the speed of light in both media. The refractive index of one medium with respect to another is defined as the ratio of the speed of light in the second medium to the speed of light in the first medium.
The refractive index of medium A with respect to medium B, denoted as \(n_{AB}\) or \(n_{A \text{ w.r.t. } B}\), is given by the ratio of the speed of light in medium B to the speed of light in medium A.
\[ n_{AB} = \frac{\text{Speed of light in medium B}}{\text{Speed of light in medium A}} = \frac{v_B}{v_A} \]The \(10^8 \text{ m/sec}\) terms cancel out.
\[ n_{AB} = \frac{2.25}{2} = 1.125 \]A) 1.125 is the correct answer. This value is obtained by correctly applying the definition of refractive index of medium A with respect to medium B, which is the ratio of the speed of light in medium B to the speed of light in medium A.
Simplify: 62 + 72 + \(\sqrt{16}\)
To simplify the given expression, we need to perform the operations in the correct order. This involves calculating squares, finding the square root, and then adding the results. The expression is \(6^2 + 7^2 + \sqrt{16}\).
Thus, the simplified value of the expression is 89.
Correct Option: B) 89
The question asks to identify the Indian state where the Chhota Nagpur Plateau is primarily located. This requires knowledge of the geographical distribution of major plateaus in India.
Correct Option: D) Jharkhand is the state where the Chhota Nagpur Plateau is primarily located. It is a mineral-rich region and a significant geographical feature of the state.
To solve this problem, we need to use the formula for average speed, which is total distance divided by total time. We will calculate the time taken for the first part of the journey, then determine the total time required to achieve the desired average speed. Finally, we will find the time available for the remaining distance and use it to calculate the speed needed for that segment.
Identify given information:
Calculate the time taken for the first part of the journey:
The formula for time is \(\text{Time} = \frac{\text{Distance}}{\text{Speed}}\).
\[ T_1 = \frac{D_1}{S_1} = \frac{300 \text{ km}}{50 \text{ km/h}} = 6 \text{ hours} \]Calculate the total time required for the entire journey to achieve the desired average speed:
Using the average speed formula: \[\text{Average Speed} = \frac{\text{Total Distance}}{\text{Total Time}}\].
So, \[\text{Total Time} = \frac{\text{Total Distance}}{\text{Average Speed}}\].
\[ T_{\text{total}} = \frac{D_{\text{total}}}{S_{\text{avg}}} = \frac{800 \text{ km}}{60 \text{ km/h}} = \frac{80}{6} \text{ hours} = \frac{40}{3} \text{ hours} \]Calculate the remaining distance:
\[ D_2 = D_{\text{total}} - D_1 = 800 \text{ km} - 300 \text{ km} = 500 \text{ km} \]Calculate the time available for the remaining distance:
\[ T_2 = T_{\text{total}} - T_1 = \frac{40}{3} \text{ hours} - 6 \text{ hours} \]\[ T_2 = \frac{40}{3} - \frac{18}{3} = \frac{22}{3} \text{ hours} \]Calculate the speed required for the remaining distance:
The formula for speed is \(\text{Speed} = \frac{\text{Distance}}{\text{Time}}\).
\[ S_2 = \frac{D_2}{T_2} = \frac{500 \text{ km}}{\frac{22}{3} \text{ hours}} \]\[ S_2 = 500 \times \frac{3}{22} = \frac{1500}{22} = \frac{750}{11} \text{ km/h} \]Correct Option: C) \( \frac{750}{11} \) km/h
When a train crosses a man walking in the opposite direction, the relative speed is the sum of their individual speeds. The distance covered is the length of the train. We will first convert all units to a consistent system (e.g., m/s), calculate the relative speed, and then convert the train's speed back to km/h.
Correct Option: C) 58.5
The question asks for the location where the World Race Walking Team Championships 2022 were held, specifically mentioning the bronze medal win by Indian athletes in the women's 20 km race walk event. This is a factual recall question related to sports events and their venues.
Correct Option: B) Oman was the host country for the World Race Walking Team Championships 2022, where the Indian women's team secured a bronze medal in the 20 km race walk event.
The question asks to identify the constitutional feature that signifies the presence of governments at both the state and central levels in India. We need to evaluate each option based on its definition and relevance to this characteristic.
D) Federalism — Federalism is precisely the feature that describes the existence of multiple levels of government (Centre and States) with their own powers and responsibilities, as seen in the Indian Constitution.
This problem involves analyzing inequalities to determine the validity of given conclusions based on a provided statement. We need to combine the parts of the statement and then check each conclusion against the derived relationships.
A) Only conclusion II is correct because, as derived from the statement \(T = S \ge N = A\), we can establish that \(T \ge A\), which means \(A \le T\).
In the given chemical reaction, which of the following chemical species acts as an oxidising agent and as a reducing agent, respectively?
2Al + Fe2O3 → Al2O3 + 2Fe
To identify the oxidising and reducing agents, we need to determine the change in oxidation states of the elements involved in the given redox reaction. An oxidising agent is a substance that gets reduced (gains electrons), and a reducing agent is a substance that gets oxidised (loses electrons).
Write down the chemical reaction:
\[ 2\text{Al} + \text{Fe}_2\text{O}_3 \rightarrow \text{Al}_2\text{O}_3 + 2\text{Fe} \]
Determine the oxidation states of each element in the reactants:
In \(2\text{Al}\): Aluminium is in its elemental form, so its oxidation state is \(0\).
\[ \text{Al}^0 \]
In \(\text{Fe}_2\text{O}_3\): Oxygen usually has an oxidation state of \(-2\). Let the oxidation state of Iron be \(x\).
\[ 2(x) + 3(-2) = 0 \ 2x - 6 = 0 \ 2x = 6 \ x = +3 \]
So, Iron is \(\text{Fe}^{+3}\) and Oxygen is \(\text{O}^{-2}\).
Determine the oxidation states of each element in the products:
In \(\text{Al}_2\text{O}_3\): Oxygen usually has an oxidation state of \(-2\). Let the oxidation state of Aluminium be \(y\).
\[ 2(y) + 3(-2) = 0 \ 2y - 6 = 0 \ 2y = 6 \ y = +3 \]
So, Aluminium is \(\text{Al}^{+3}\) and Oxygen is \(\text{O}^{-2}\).
In \(2\text{Fe}\): Iron is in its elemental form, so its oxidation state is \(0\).
\[ \text{Fe}^0 \]
Identify changes in oxidation states:
Aluminium: From \(\text{Al}^0\) (reactant) to \(\text{Al}^{+3}\) (product). The oxidation state increased, so Aluminium is oxidised.
Iron: From \(\text{Fe}^{+3}\) (reactant) to \(\text{Fe}^0\) (product). The oxidation state decreased, so Iron is reduced.
Oxygen: Remains \(-2\) in both reactants and products, so it is neither oxidised nor reduced.
Identify the oxidising and reducing agents:
Since Aluminium (\(\text{Al}\)) is oxidised, it acts as the reducing agent.
Since Iron (\(\text{Fe}\)) in \(\text{Fe}_2\text{O}_3\) is reduced, \(\text{Fe}_2\text{O}_3\) acts as the oxidising agent.
The question asks for the oxidising agent and reducing agent, respectively.
Oxidising agent: \(\text{Fe}_2\text{O}_3\)
Reducing agent: \(\text{Al}\)
Correct Option: C) \(\text{Fe}_2\text{O}_3\) and \(\text{Al}\)
A) Al and Fe: This incorrectly identifies Fe as the reducing agent. Fe is a product and is in its reduced form.
B) Fe and Al: This incorrectly identifies Fe as the oxidising agent. Fe is a product and is in its reduced form. Al is correctly identified as the reducing agent.
D) \(\text{Al}_2\text{O}_3\) and Fe: Both \(\text{Al}_2\text{O}_3\) and Fe are products of the reaction, not reactants that act as agents.