An integrated scheme for school education, ‘Samagra Shiksha Scheme’ of the Government of India has been continued for which of the following periods?
2019-20 to 2024-25
2020-21 to 2025-26
2021-22 to 2025-26
2021-22 to 2026-27
The question asks for the period for which the Samagra Shiksha Scheme, an integrated scheme for school education by the Government of India, has been continued. This requires knowledge of recent government policy decisions regarding the scheme's extension.
C) 2021-22 to 2025-26. This period accurately reflects the five-year extension approved by the Government of India for the Samagra Shiksha Scheme, starting from the financial year 2021-22 and concluding in 2025-26.
The question asks to identify the tiny pores found on plant leaves. This is a direct knowledge-based question related to plant anatomy and physiology.
Correct Option: D) Stomata
Stomata (singular: stoma) are minute pores, typically found on the epidermis of leaves, stems, and other organs, that are used to control the rate of gas exchange. They are bordered by a pair of specialized parenchyma cells known as guard cells that are responsible for regulating the size of the stomatal opening.
Study the given table and answer the following question.
| Number of cushions sold in | ||
| February | March | |
| Store X | 196 | 114 |
| Store Y | 72 | 98 |
| Store Z | 84 | 155 |
The total number of cushions sold by Store X in February and March is what percentage more than the number of cushions sold by Store Z in March?
To solve this problem, we need to extract the relevant data from the given table. First, calculate the total number of cushions sold by Store X in February and March. Then, identify the number of cushions sold by Store Z in March. Finally, use these two values to calculate the percentage by which the total sales of Store X are more than the sales of Store Z in March.
Find the total number of cushions sold by Store X in February and March:
From the table:
Total cushions sold by Store X = \(196 + 114 = 310\)
Find the number of cushions sold by Store Z in March:
From the table:
Calculate the percentage more:
The formula to calculate what percentage 'A' is more than 'B' is:
\[ \text{Percentage more} = \left( \frac{\text{A} - \text{B}}{\text{B}} \right) \times 100\% \]Here, A = Total cushions sold by Store X = 310
B = Cushions sold by Store Z in March = 155
Substitute the values into the formula:
\[ \text{Percentage more} = \left( \frac{310 - 155}{155} \right) \times 100\% \]\[ \text{Percentage more} = \left( \frac{155}{155} \right) \times 100\% \]\[ \text{Percentage more} = 1 \times 100\% \]\[ \text{Percentage more} = 100\% \]B) 100%
With reference to cost, what is the full form of SMC from the following?
Short run Marginal Cost
Subjective Marginal Cost
Special Marginal Cost
Silent Marginal Cost
The question asks for the full form of "SMC" in the context of cost. This is a standard abbreviation used in economics, specifically in microeconomics when discussing production costs.
A) Short run Marginal Cost is the correct full form of SMC in the context of cost in economics. Short run Marginal Cost (SMC) is the change in total cost resulting from producing one additional unit of output in the short run, where some factors of production are fixed.
Which two numbers, from among the given options, should be interchanged to make the given equation correct?
21 ÷ 9 + 99 − 81 × 5 = 3
The problem requires us to identify which two numbers, when interchanged in the given equation, will make the equation mathematically correct. We will test each option by interchanging the specified numbers and then evaluating the expression using the order of operations (BODMAS/PEMDAS).
The given equation is:
\[ 21 \div 9 + 99 - 81 \times 5 = 3 \]Let's evaluate the left-hand side (LHS) of the original equation first to see if it's already correct:
\[ 21 \div 9 + 99 - 81 \times 5 \]\[ 2.33... + 99 - 405 \]Since \(2.33... + 99 - 405\) is clearly not equal to \(3\), the equation is incorrect as given.Now, let's test each option:
The equation becomes:
\[ 21 \div 81 + 99 - 9 \times 5 \]\[ 0.259... + 99 - 45 \]\[ 99.259... - 45 \]\[ 54.259... \]This is not equal to \(3\). So, option A is incorrect.The equation becomes:
\[ 81 \div 9 + 99 - 21 \times 5 \]Now, let's evaluate this expression:
Since the LHS equals \(3\), which is the RHS, this interchange makes the equation correct.
B) Interchanging 21 and 81 makes the equation correct:
\[ 81 \div 9 + 99 - 21 \times 5 = 9 + 99 - 105 = 108 - 105 = 3 \]The question asks to identify the largest fair in West Bengal. This requires knowledge of the major fairs and festivals celebrated in the state and their relative scale or attendance.
Correct Option: B) Gangasagar Mela is the largest fair of West Bengal. It is an annual pilgrimage and fair held on Sagar Island (Gangasagar) in the Sundarbans, where the Ganges River meets the Bay of Bengal. It attracts millions of pilgrims from across India and the world, especially during Makar Sankranti, making it the largest fair in the state and one of the largest religious gatherings globally.
The 73rd and 74th Amendments to the Indian Constitution provide for elections to local bodies _____.
after every five years
after every three years
after every two years
every year
The question asks about the frequency of elections to local bodies as mandated by the 73rd and 74th Amendments to the Indian Constitution. This requires knowledge of the provisions related to Panchayati Raj Institutions and Municipalities.
Correct Option: A) after every five years
The question asks for the founding year of AU Small Finance Bank. This is a factual question requiring knowledge of the bank's history.
B) 1996 — AU Small Finance Bank was originally founded as AU Financiers (India) Ltd. in 1996. It began its operations as a Small Finance Bank in 2017 after receiving the license in 2015, but its foundation as a financial entity dates back to 1996.
Express 3.\(\overline{31}\) in the form \( \frac{p}{q} \), where p and q are integers and q ≠ 0.
\(\frac{329}{99}\)
\(\frac{109}{33}\)
\(\frac{10}{3}\)
\(\frac{328}{99}\)
To express a repeating decimal in the form \(\frac{p}{q}\), we use an algebraic method. We set the given decimal equal to a variable, multiply it by powers of 10 to shift the decimal point, and then subtract the original equation from the modified one to eliminate the repeating part.
Let \(x\) be the given repeating decimal:
\[ x = 3.\overline{31} \]This means \(x = 3.313131...\)
Since two digits are repeating, multiply both sides of the equation by \(10^2 = 100\):
\[ 100x = 331.313131... \]Now, subtract the first equation (\(x = 3.313131...\)) from the second equation (\(100x = 331.313131...\)):
\[ 100x - x = 331.313131... - 3.313131... \]This simplifies to:
\[ 99x = 328 \]Solve for \(x\) by dividing both sides by 99:
\[ x = \frac{328}{99} \]Thus, \(3.\overline{31}\) expressed in the form \(\frac{p}{q}\) is \(\frac{328}{99}\).
D) \(\frac{328}{99}\) is the correct representation of \(3.\overline{31}\) as a fraction.
We are given the sum of two numbers and their HCF. We need to find the number of possible pairs of such numbers where one number is greater than the other. We can express the numbers in terms of their HCF and co-prime factors.
Correct Option: D) 2