The value of the expression (1 + \( \frac{1}{3} \))(1 + \( \frac{1}{4} \))(1 + \( \frac{1}{5} \))…(1 + \(\frac{1}{n-1}\)) is:
\( \frac{n}{3} \)
\( \frac{1}{3} \)
1 + \( \frac{1}{n} \)
\(\frac{n}{n-1}\)
The sum of 3.\(\overline{26}\) - 2.\(\overline{14}\)+ 1.\(\overline{33}\) is:
2.\(\overline{45}\)
2.\(\overline{25}\)
2.\(\overline{15}\)
2.\(\overline{55}\)
If (x + \( \frac{1}{x} \)) = 7, then (x - \( \frac{1}{x} \)) is equal to:
Solve the given equation.
\(\frac{3+4\div2\times3}{4+3\times2\div3}\) =
\( \frac{3}{5} \)
\( \frac{5}{4} \)
\( \frac{3}{4} \)
\( \frac{3}{2} \)