A dice is thrown twice and the sum of the appearing numbers is 10. Then the probability that the number 5 has appeared at least once is:
\( \frac{1}{4} \)
\( \frac{1}{3} \)
\( \frac{2}{3} \)
\( \frac{1}{2} \)
B. \( \frac{1}{3} \)