What is the compound interest on ₹2,800 for 1\( \frac{1}{2} \) years at 10% per annum compounded half-yearly?
If x = \(\frac{\sqrt{9}+1}{\sqrt{9}-1}\) and y = \(\frac{\sqrt{16}+1}{\sqrt{16}-1}\), then the value of (x² - y²) is:
\( \frac{11}{9} \)
\( \frac{6}{5} \)
\( \frac{7}{6} \)
\( \frac{9}{8} \)
Simplify the following.
1 + \(\frac{3}{7}\times\left[6+8\times(3-2)\right]+\left\{\left(\frac{1}{5}\div\frac{7}{25}\right)-\left(\frac{3}{7}+\frac{4}{14}\right)\right\}\)}