The question asks to identify which of the given options is NOT a Navratna company. To answer this, one needs to know the list of Public Sector Undertakings (PSUs) that have been granted Navratna status by the Government of India.
Correct Option: C) Airports Authority of India
The question asks to identify the relationship between the first two terms and apply the same relationship to find the fourth term for the given third term. This is an analogy-based reasoning question.
Correct Option: D) Painter — A painter uses a wall as a surface to apply paint, just as an artist uses a canvas to create art.
This question tests basic scientific understanding, specifically the conditions required for combustion (burning). Fire needs three things to burn: fuel, heat, and oxygen. This is often referred to as the "fire triangle".
C) It will stop burning — This is correct because covering the candle with a glass jar cuts off the supply of fresh oxygen. As the existing oxygen inside the jar is consumed by the flame, the combustion process cannot continue, and the flame will extinguish.
The question asks about the number of biodiversity hotspots that India hosts. To answer this, one needs to recall the globally recognized biodiversity hotspots and identify which ones are located either entirely within India or significantly extend into India.
D) Four. India hosts four major biodiversity hotspots: the Himalayas, the Western Ghats, the Indo-Burma Region, and Sundaland (which includes the Nicobar Islands).
To answer this question, one needs to recall the geographical boundaries of India and its neighboring country, Bangladesh. Specifically, identifying which Indian states share a land border with Bangladesh is crucial.
B) Five. The five Indian states that share a border with Bangladesh are West Bengal, Assam, Meghalaya, Tripura, and Mizoram.
This problem involves calculating compound interest for two different individuals with different interest rates over the same period and then finding the initial investment based on the difference in their earned interests. We will use the formula for compound interest to find the total amount and then subtract the principal to get the interest earned. Finally, we'll set up an equation based on the given difference in interest to solve for the initial investment.
Define variables:
Let the initial sum invested by each person be \(P\).
Time period \(T = 2\) years.
Calculate interest for Rafique:
Rafique's interest rate \(R_R = 15\%\) per annum.
The formula for amount with compound interest is \(A = P \left(1 + \frac{R}{100}\right)^T\).
Amount for Rafique \[A_R = P \left(1 + \frac{15}{100}\right)^2 = P \left(1 + 0.15\right)^2 = P (1.15)^2\].
\[ A_R = P \times 1.3225 \]Interest earned by Rafique \(I_R = A_R - P = P(1.3225 - 1) = 0.3225P\).
Calculate interest for Pritam:
Pritam's interest rate \(R_P = 10\%\) per annum.
Amount for Pritam \[A_P = P \left(1 + \frac{10}{100}\right)^2 = P \left(1 + 0.10\right)^2 = P (1.10)^2\].
\[ A_P = P \times 1.21 \]Interest earned by Pritam \(I_P = A_P - P = P(1.21 - 1) = 0.21P\).
Set up the equation based on the difference in interest:
Given that Rafique earns ₹2,250 more as interest than Pritam.
\[ I_R - I_P = 2250 \]\[ 0.3225P - 0.21P = 2250 \]\[ 0.1125P = 2250 \]
Solve for P:
\[ P = \frac{2250}{0.1125} \]To simplify the division, multiply the numerator and denominator by 10000:
\[ P = \frac{2250 \times 10000}{1125} \]\[ P = \frac{22500000}{1125} \]We know that \(1125 \times 2 = 2250\). So, \(2250 / 1125 = 2\).
\[ P = 2 \times 10000 \]\[ P = 20000 \]
Thus, each of them invested ₹20,000 initially.
The question asks to identify the state that does NOT share a border with Mizoram. This requires knowledge of the geographical boundaries of Mizoram with its neighboring Indian states.
A) Meghalaya does not share its border with Mizoram. Assam lies between Meghalaya and Mizoram.
This question tests knowledge about the administrative jurisdiction of various ministries in the Government of India, specifically regarding mineral resources. Understanding which ministry is responsible for different types of minerals is key.
C) Copper — Copper is a non-ferrous metallic mineral. The exploration, mining, and regulation of copper and other non-coal, non-atomic, and non-hydrocarbon minerals fall under the direct purview of the Ministry of Mines. This includes policy formulation, legislation, and administration of the Mines and Minerals (Development and Regulation) Act, 1957, for all mines and minerals other than coal, lignite, and major minerals of atomic energy.
The problem asks us to find the second number given the sum of three numbers and the relationships between them. We can set up algebraic equations based on the given relationships and then solve for the value of the second number.
Let the three numbers be \(x\), \(y\), and \(z\).
According to the problem statement, the sum of the three numbers is 253:
\[ x + y + z = 253 \quad \text{(Equation 1)} \]The first number is twice the second number. So, we can write:
\[ x = 2y \quad \text{(Equation 2)} \]The third number is one-third of the first number. So, we can write:
\[ z = \frac{1}{3}x \quad \text{(Equation 3)} \]Our goal is to find the value of the second number, \(y\). We can express \(x\) and \(z\) in terms of \(y\) and substitute them into Equation 1.
From Equation 2, we already have \(x\) in terms of \(y\):
\[ x = 2y \]Now, substitute \(x = 2y\) into Equation 3 to express \(z\) in terms of \(y\):
\[ z = \frac{1}{3}(2y) = \frac{2y}{3} \]Substitute the expressions for \(x\) and \(z\) in terms of \(y\) into Equation 1:
\[ (2y) + y + \left(\frac{2y}{3}\right) = 253 \]Combine the terms with \(y\):
\[ 3y + \frac{2y}{3} = 253 \]To add the terms, find a common denominator, which is 3:
\[ \frac{3 \times 3y}{3} + \frac{2y}{3} = 253 \] \[ \frac{9y}{3} + \frac{2y}{3} = 253 \] \[ \frac{9y + 2y}{3} = 253 \] \[ \frac{11y}{3} = 253 \]Now, solve for \(y\):
\[ 11y = 253 \times 3 \] \[ 11y = 759 \] \[ y = \frac{759}{11} \]Perform the division:
\[ y = 69 \]Thus, the second number is 69.
Correct Option: C) 69
This problem involves concepts of work and time. We are given the efficiency of John relative to Jesse and the time John takes to complete a work alone. We need to find the time taken by both of them working together. We can solve this by calculating individual work rates and then combining them.
To add these fractions, find a common denominator, which is 70.
\[ \text{Combined 1-day work} = \frac{2}{70} + \frac{5}{70} = \frac{2+5}{70} = \frac{7}{70} = \frac{1}{10} \text{ unit/day} \]D) 10 days is the correct answer, as calculated above.