Out of Harish's monthly salary of ₹45,000, \( \frac{1}{3} \) is spent on education and \( \frac{2}{6} \) on food and other necessities. The rest of the salary goes towards his savings. The amount of savings is:
If \( \tan\theta = \frac{3}{5} \), then the value of \( \frac{1 + \tan\theta}{1 - \cot\theta} \) is:
\( \frac{11}{5} \)
-\( \frac{8}{5} \)
\( \frac{2}{5} \)
-\( \frac{12}{5} \)