The question asks about the cities connected by India's first bullet train project. This is a factual question related to current affairs and infrastructure development in India. Identifying the correct route requires knowledge of major government projects.
The first high-speed rail corridor, often referred to as the bullet train project, is the Mumbai-Ahmedabad High-Speed Rail (MAHSR) project. This project is being implemented with technical and financial assistance from Japan.
B) Mumbai and Ahmedabad: The Mumbai-Ahmedabad High-Speed Rail Corridor is India's first bullet train project, connecting these two major cities. Construction is actively underway, and it is a flagship infrastructure initiative.
The question asks to identify the most polluted city in the world according to the Guinness World Records 2020 analysis of a World Health Organization (WHO) report. This requires specific knowledge of environmental reports and their findings from that particular year.
Correct Option: A) Kanpur was recognized as the most polluted city in the world by the Guinness World Records 2020, based on a World Health Organization report that analyzed PM2.5 levels.
The question asks to identify the article of the Indian Constitution that deals with the formation of the Finance Commission. This requires knowledge of specific articles related to constitutional bodies.
Correct Option: C) Article 280
Raj is 60% more efficient than Sundar, and Sundar can finish a certain job in 16 days. How many days does Raj alone take to complete the same job?
This problem involves concepts of work and time. We need to relate the efficiency of Raj and Sundar to find out how many days Raj takes to complete the job. Efficiency is inversely proportional to the time taken to complete a job.
Understand the efficiency relationship: Raj is 60% more efficient than Sundar. If Sundar's efficiency is \(E_S\), then Raj's efficiency \(E_R\) can be expressed as:
\[ E_R = E_S + 0.60 \times E_S = 1.60 \times E_S \]This means Raj's efficiency is 1.6 times Sundar's efficiency.
Relate efficiency to time: Efficiency is inversely proportional to the time taken to complete a job. Let \(T_S\) be the time Sundar takes and \(T_R\) be the time Raj takes. So, we have:
\[ \frac{E_R}{E_S} = \frac{T_S}{T_R} \]Substitute known values: We know that \(E_R = 1.6 \times E_S\) and \(T_S = 16\) days. Substitute these into the ratio:
\[ \frac{1.6 \times E_S}{E_S} = \frac{16}{T_R} \] \[ 1.6 = \frac{16}{T_R} \]Solve for \(T_R\): Now, we can find the time Raj takes:
\[ T_R = \frac{16}{1.6} \] \[ T_R = \frac{160}{16} \] \[ T_R = 10 \text{ days} \]Correct Option: C) 10 days
The question asks to identify the folk dance that is NOT associated with the state of Assam. This requires knowledge of various folk dances and their respective states of origin or association.
Correct Option: C) Kathi
Kathi is a folk dance primarily associated with the state of West Bengal. It is a martial dance performed by men, often during festivals like Durga Puja.
The question asks to identify the noble gas detected on the lunar exosphere by the Chandrayaan-2 orbiter in October 2019. This is a factual question related to space exploration and scientific discoveries.
Correct Option: B) Argon
In October 2019, the Chandrayaan-2 orbiter, specifically its CHACE-2 payload, detected Argon-40 in the lunar exosphere. This was a significant discovery, helping scientists understand the Moon's tenuous atmosphere and the processes that release gases from its surface.
To find the least square number exactly divisible by a set of numbers, we first need to find the Least Common Multiple (LCM) of those numbers. Then, we need to make the LCM a perfect square by multiplying it by the smallest possible integer that makes all prime factors have even powers.
Correct Option: A) 1600
The question asks to identify the type of frictional force that is generally the least. We need to understand the characteristics of each type of friction listed in the options and compare their magnitudes.
Correct Option: D) Rolling friction is the least frictional force among the given options. This is because rolling involves minimal actual sliding between surfaces, primarily involving deformation of the surfaces at the point of contact, which requires less energy to overcome compared to sliding or static friction.
This question tests knowledge about the locations of major atomic power stations in India. To answer correctly, one needs to recall the state where the Kaiga Atomic Power Station is located.
Correct Option: B) Karnataka
A bought a horse for ₹4,500. He sold it to B at a profit of 5%. B sold it to C at a profit of 20%. Then the cost price of the horse for C is:
This problem involves successive profit calculations. We need to calculate the selling price of the horse from A to B, which then becomes the cost price for B. Then, we calculate the selling price from B to C, which will be the cost price for C.
Calculate the selling price from A to B:
A bought the horse for ₹4,500 and sold it at a profit of 5%.
Cost Price for A (\(CP_A\)) = ₹4,500
Profit percentage for A = 5%
Selling Price for A (\(SP_A\)) = \(CP_A + \text{Profit}\)
Profit = \(5\%\) of \(CP_A = \frac{5}{100} \times 4500 = 5 \times 45 = \text{₹}225\)
So, \(SP_A = 4500 + 225 = \text{₹}4,725\)
Alternatively, \[SP_A = CP_A \times (1 + \frac{\text{Profit \%}}{100}) = 4500 \times (1 + \frac{5}{100}) = 4500 \times \frac{105}{100} = 45 \times 105 = \text{₹}4,725\]
Determine the cost price for B:
The selling price for A is the cost price for B.
Cost Price for B (\(CP_B\)) = \(SP_A = \text{₹}4,725\)
Calculate the selling price from B to C:
B sold the horse to C at a profit of 20%.
Profit percentage for B = 20%
Selling Price for B (\(SP_B\)) = \(CP_B + \text{Profit}\)
Profit = \(20\%\) of \[CP_B = \frac{20}{100} \times 4725 = \frac{1}{5} \times 4725 = \text{₹}945\]
So, \(SP_B = 4725 + 945 = \text{₹}5,670\)
Alternatively, \[SP_B = CP_B \times (1 + \frac{\text{Profit \%}}{100}) = 4725 \times (1 + \frac{20}{100}) = 4725 \times \frac{120}{100} = 4725 \times \frac{6}{5}\]
\[ SP_B = \frac{4725 \times 6}{5} = 945 \times 6 = \text{₹}5,670 \]Determine the cost price for C:
The selling price for B is the cost price for C.
Cost Price for C (\(CP_C\)) = \(SP_B = \text{₹}5,670\)
B) ₹5,670