If the area of a square is 11025 cm², then the length of its diagonal is:
105\(\sqrt{2}\) cm
125\(\sqrt{2}\) cm
135\(\sqrt{2}\) cm
115\(\sqrt{2}\) cm
Simplify the given expression:
[13 − (−2) × {6 − (7 − 3)}] ÷ [4 × {5 + (−2) × (−6)}]
\( \frac{1}{4} \)
\( \frac{7}{34} \)
\( \frac{-17}{68} \)
\( \frac{-1}{3} \)