Study the given grid carefully and select the option from among the given options that can replace the question mark (?).
| B3 | E4 | H7 |
| K8 | N9 | ? |
| T11 | W13 | Z24 |
The question gives a 3 × 3 grid with rows B3, E4, H7; K8, N9, ?; and T11, W13, Z24, and asks for the missing term. We need to find the pattern in the letters and the pattern in the numbers separately and combine them.
Identify the given information:
Find the letter pattern:
Reading row by row, the letters are B, E, H, K, N, ?, T, W, Z. Each letter moves 3 places forward:
\[ \text{N}(14)+3=17=\text{Q} \]Check: Q (17) + 3 = 20 (T).
Find the number pattern:
In each row, the third number is the sum of the first two:
\[ 3+4=7 \] \[ 11+13=24 \]Applying this to the second row:
\[ 8+9=17 \]Combine the results:
The missing term is Q17.
Correct Option: C) Q17 — The letters advance by 3 places (N → Q), and the third number in each row is the sum of the first two (8 + 9 = 17). Hence, Option C is the correct answer.
A) Q21: This is incorrect because the letter is right but the number should be 8 + 9 = 17, not 21.
B) R12: This is incorrect because the letter should be Q (N + 3) and the number should be 17.
D) P12: This is incorrect because the letter should be Q (N + 3) and the number should be 17.
The question asks to identify the first Indian individual to travel to space. This is a factual question related to Indian space history.
Correct Option: D) Rakesh Sharma was the first Indian citizen to travel to space. He flew aboard the Soviet Soyuz T-11 spacecraft as part of the Intercosmos programme on April 3, 1984.
The question gives five men facing south in one line and five women facing north in a parallel line, with clues about who sits opposite, beside or diagonally opposite whom, and asks which pair is diagonally opposite. We need to number the seats from 1 (west end) to 5 (east end) for both lines, convert each "left" and "right" according to the direction each person faces, and build the arrangement.
Identify the given information:
Place the women L1, L3 and L4:
L3 is to the immediate right of L1, and L4 is to the immediate right of L3. So, L1, L3 and L4 sit consecutively from west to east. Since L1 is at an end, L1 is at seat 1, L3 at seat 2 and L4 at seat 3.
Place M4, M5 and M2:
M5 is opposite L3, so M5 is at seat 2. M4 is opposite L4, so M4 is at seat 3. M2 is to the immediate left of M4; for a man facing south, left is east, so M2 is at seat 4. M2 is opposite L5, so L5 is at seat 4.
Place the remaining persons:
L2 takes the remaining women's seat 5. M3 is diagonally opposite L2, so M3 is at seat 1. M1 takes the remaining seat 5.
Men (seats 1 to 5): M3, M5, M4, M2, M1.
Women (seats 1 to 5): L1, L3, L4, L5, L2.
Find the diagonally opposite pairs:
M3 (seat 1) is diagonally opposite L2 (seat 5), and M1 (seat 5) is diagonally opposite L1 (seat 1).
Correct Option: D) M1 and L1 — M1 sits at the east end of the men's line and L1 sits at the west end of the women's line, so they are diagonally opposite each other. Hence, Option D is the correct answer.
A) M5 and L3: This is incorrect because M5 sits directly opposite L3, not diagonally opposite.
B) M1 and L2: This is incorrect because M1 and L2 are both at seat 5, so they sit directly opposite each other.
C) M3 and L1: This is incorrect because M3 and L1 are both at seat 1, so they sit directly opposite each other.
The question asks for the year when the National Programme of Nutritional Support to Primary Education (NP-NSPE), commonly known as the Mid-Day Meal Scheme, was launched in India. This is a factual question requiring knowledge of the history of social welfare programs in India.
C) 1995 — The National Programme of Nutritional Support to Primary Education (NP-NSPE) was initiated by the Government of India on August 15, 1995. This program is widely known as the Mid-Day Meal Scheme, which provides free lunches on working days for children in primary and upper primary classes in government, government-aided, local body, Education Guarantee Scheme, and Alternative Innovative Education centres, Madarsa and Maqtabs supported under Sarva Shiksha Abhiyan.
The question asks for the full form of the acronym EVM. This is a general knowledge question related to Indian elections and common terminology used in that context.
Correct Option: A) Electronic Voting Machine is the correct full form of EVM. These machines are used in India for conducting elections, allowing voters to cast their votes electronically instead of using paper ballots.
Big Mart is offering 5% discount on card payment. How much percentage above cost price should the marked price be so as to make a profit of 10%?
14 \( \frac{16}{19} \) %
16 \( \frac{14}{19} \) %
15 \( \frac{5}{19} \) %
15 \( \frac{15}{19} \) %
To solve this problem, we need to relate the Cost Price (CP), Selling Price (SP), Marked Price (MP), discount percentage, and profit percentage. We will assume a convenient Cost Price, calculate the required Selling Price to achieve the desired profit, and then use the discount percentage to find the Marked Price. Finally, we will calculate the percentage by which the Marked Price is above the Cost Price.
Assume a Cost Price (CP):
Let the Cost Price (CP) of the item be \( \text{₹}100 \).
Calculate the required Selling Price (SP):
The desired profit is 10%.
Profit \( = 10\% \) of CP
\[ \text{Profit} = \frac{10}{100} \times 100 = \text{₹}10 \]Thus, the Selling Price (SP) must be:
\[ \text{SP} = \text{CP} + \text{Profit} = 100 + 10 = \text{₹}110 \]So, the item must be sold for \( \text{₹}110 \) to make a 10% profit.
Relate Selling Price (SP) to Marked Price (MP) using the discount:
A 5% discount is offered on card payment, which means the SP is 95% of the MP.
\[ \text{SP} = \text{MP} - (5\% \text{ of MP}) = \text{MP} \times \left(1 - \frac{5}{100}\right) = \text{MP} \times \frac{95}{100} \]
We know \( \text{SP} = \text{₹}110 \). So,
\[ 110 = \text{MP} \times \frac{95}{100} \]
Now, calculate the Marked Price (MP):
\[ \text{MP} = 110 \times \frac{100}{95} = \frac{11000}{95} \]
Simplify the fraction:
\[ \text{MP} = \frac{2200}{19} \text{ (by dividing numerator and denominator by 5)} \]
Calculate the percentage above Cost Price:
We need to find how much percentage the MP is above the CP.
Difference \( = \text{MP} - \text{CP} = \frac{2200}{19} - 100 \)
\[ \text{Difference} = \frac{2200 - (100 \times 19)}{19} = \frac{2200 - 1900}{19} = \frac{300}{19} \]
Percentage above CP \[= \frac{\text{Difference}}{\text{CP}} \times 100\%\]
\[ \text{Percentage above CP} = \frac{\frac{300}{19}}{100} \times 100\% \]
\[ \text{Percentage above CP} = \frac{300}{19}\% \]
Convert the improper fraction to a mixed fraction:
\[ \frac{300}{19} = 15 \frac{15}{19}\% \]
Correct Option: D) 15 \( \frac{15}{19} \) %
This is a syllogism problem, which can be solved using Venn diagrams or by combining the given statements logically. We need to find a conclusion that necessarily follows from the two given statements.
Correct Option: C) All guitars are bagpipes.
This is a classic work-and-time problem. We need to find the combined rate of work when two individuals work together. The key idea is to calculate the amount of work each person can do in one day and then sum their daily work rates to find their combined daily work rate. The reciprocal of the combined daily work rate will give the total time taken to complete the work together.
B) 12 days is the correct answer. This is obtained by calculating their individual daily work rates, summing them, and then taking the reciprocal to find the total time.
The question asks for the headquarters of UNESCO. This is a factual question related to international organizations, which is a common topic in general knowledge sections of competitive exams. Recalling the location of major international bodies is key.
Correct Option: B) Paris
The problem involves a fundamental theorem in circle geometry: the angle subtended by an arc at the center is double the angle subtended by it at any point on the remaining part of the circle. We are given the angle subtended at a point on the circumference and need to find the angle subtended by the same arc at the center.
Correct Option: B) 95°