The question asks to identify a specific geostationary communication satellite launched by ISRO for the Indian Air Force. This requires knowledge of ISRO's satellite missions and their intended purposes, particularly those related to defense communication.
B) GSAT-7A: GSAT-7A is a geostationary communication satellite launched by ISRO on December 19, 2018, aboard a GSLV-F11 rocket. It is specifically designed to provide enhanced communication capabilities for the Indian Air Force (IAF), enabling better connectivity for ground-based radars, airbases, and airborne early warning and control (AEW&C) aircraft.
The question asks to identify the outermost covering of a cell that separates its internal contents from the external environment. This requires knowledge of basic cell structure.
C) Plasma membrane is the correct answer. It is the outermost covering of an animal cell and lies just inside the cell wall in plant cells, fungi, and bacteria. Its primary function is to separate the cell's contents from the external environment and regulate the movement of substances in and out of the cell.
This problem can be solved using the concept of work and time, specifically the formula relating men, days, and work. The general formula used is \[\frac{M_1 D_1}{W_1} = \frac{M_2 D_2}{W_2}\], where \(M\) is the number of persons, \(D\) is the number of days, and \(W\) is the amount of work done.
D) 39
The question asks to identify the war associated with 'Operation Vijay'. This requires knowledge of major military operations conducted by India and their corresponding conflicts.
Correct Option: B) Kargil War-1999
'Operation Vijay' was the name given to the Indian military operation to flush out Pakistani intruders from the Kargil sector in 1999. The conflict is widely known as the Kargil War.
The question asks why Heavy Water is called so. This relates to its chemical composition and properties. We need to understand what distinguishes heavy water from normal water.
D) it uses Deuterium, a heavier isotope of hydrogen, rather than Protium. This is the correct reason. Deuterium (\(^{2}\text{H}\)) has a neutron in addition to a proton, making it heavier than Protium (\(^{1}\text{H}\)), which has only a proton. This increased atomic mass of hydrogen in heavy water (\(\text{D}_2\text{O}\)) makes the entire water molecule heavier.
The question asks to identify a high-level programming language specifically designed for scientific and mathematical use. We need to evaluate each option based on its primary purpose and application area.
Correct Option: B) FORTRAN is a high-level programming language specifically developed for scientific and mathematical computations, making it suitable for engineers and scientists.
The problem presents a series of letter pairs. To find the missing term, we need to identify the pattern in the alphabetical positions of the letters within each pair and between consecutive pairs.
A) IU — As determined by analyzing the patterns of both the first and second letters in the series, the next term is IU.
The problem involves calculating the difference in rates of interest given the principal, time, and the difference in simple interests. We will use the formula for simple interest, \(SI = \frac{P \times R \times T}{100}\), and apply it to the difference in interests.
Let \(P\) be the principal amount, \(T\) be the time, and \(R_1\) and \(R_2\) be the two different rates of interest.
Given values:
The formula for simple interest is \(SI = \frac{P \times R \times T}{100}\).
So, for the first source, \(SI_1 = \frac{P \times R_1 \times T}{100}\).
For the second source, \(SI_2 = \frac{P \times R_2 \times T}{100}\).
The difference in simple interests is:
\[ SI_1 - SI_2 = \frac{P \times R_1 \times T}{100} - \frac{P \times R_2 \times T}{100} \]\[ 10.80 = \frac{P \times T}{100} (R_1 - R_2) \]Substitute the given values of \(P\) and \(T\):
\[ 10.80 = \frac{1200 \times 3}{100} (R_1 - R_2) \]Simplify the equation:
\[ 10.80 = 12 \times 3 (R_1 - R_2) \]\[ 10.80 = 36 (R_1 - R_2) \]Now, solve for the difference in rates, \((R_1 - R_2)\):
\[ R_1 - R_2 = \frac{10.80}{36} \]\[ R_1 - R_2 = 0.3 \]The difference between their rates of interest is \(0.3\%\).
Correct Option: C) 0.3%
To find the Least Common Multiple (LCM) of a set of numbers, we can use the prime factorization method. This involves finding the prime factors of each number and then taking the highest power of each common and uncommon prime factor.
The prime factors involved are 2 and 3.
Multiply the highest powers of all prime factors:
\[ \text{LCM}(36, 72, 144) = 2^4 \times 3^2 = 16 \times 9 = 144 \]Alternatively, we can observe that 36 is a factor of 72 (\(36 \times 2 = 72\)), and 72 is a factor of 144 (\(72 \times 2 = 144\)). When one number is a multiple of all other numbers in the set, that largest number is the LCM. In this case, 144 is a multiple of both 36 and 72.
Correct Option: B) 144
The question asks to identify the largest freshwater lake in North-East India from the given options. This requires knowledge of the geographical locations and characteristics of prominent Indian lakes.
Correct Option: C) Loktak Lake is located in Manipur, one of the North-Eastern states of India, and is known as the largest freshwater lake in the region.