Find the value of n in the given equation.271.5 × 91.25 ÷ 35 = 3n
6
4
9
2
D. 2
The value of \(\frac{1+\tan^2\theta}{1+\cot^2\theta}\) is:
\( \tan ^{2}\theta \)
\( \cot ^{2}\theta \)
\( \sec ^{2}\theta \)
\( \operatorname{cosec} ^{2}\theta \)
A. \( \tan ^{2}\theta \)