Simplify 1.\(\overline{45}\) + 0.\(\overline{312}\) − 1.\(\overline{112}\).
\( \frac{589}{900} \)
\( \frac{13}{20} \)
\( \frac{374}{495} \)
\( \frac{163}{300} \)
If every 3rd letter from left to right of English alphabet is deleted, then what would be the 12th letter from right in the new series obtained?
What is the value of 3 \( \frac{21}{23} \)÷ 3 \( \frac{15}{31} \)?