If sinθ − cosθ = 0, (angle in first quadrant) then the value of sin³θ + 3cos³θ is:
\(\frac{1}{\sqrt{2}}\)
2
\(\sqrt{2}\)
2\(\sqrt{2}\)
C. \(\sqrt{2}\)
Simplify.\(\sqrt{56+\sqrt{185+88\sqrt{\sqrt{36}+19}}}\)
\(\sqrt{91}\)
81
9
3
C. 9