The question asks for the full form of 'MRTP' as in the MRTP Act of 1969. This is a direct recall question about a significant piece of Indian economic legislation. Knowing the full name of such acts is crucial for competitive exams.
The MRTP Act, 1969, was enacted to ensure that the operation of the economic system does not result in the concentration of economic power to the common detriment, for the control of monopolies, and for the prohibition of monopolistic and restrictive trade practices.
B) Monopolies and Restrictive Trade Practices Act. This is the accurate full form of the MRTP Act, 1969. It correctly identifies the two main aspects the Act sought to regulate: monopolies and trade practices that restrict competition.
The question asks for the founding year of the Asiatic Society by Sir William Jones. This is a direct factual recall question from Indian history, specifically related to the British colonial period and the intellectual movements of that era.
Correct Option: A) 1784
Sir William Jones founded the Asiatic Society in Calcutta on January 15, 1784. The society was established to encourage oriental research and to study the history, antiquities, arts, sciences, and literature of Asia.
This question is based on letter coding and decoding. To determine the code for CASPTL, we must identify the transformation used to convert BUREAK into PZVIFY. The coding pattern involves two steps: first, reverse the order of the letters in the given word, and then replace each letter with its opposite letter in the English alphabet. The opposite letters are paired as A-Z, B-Y, C-X, D-W, and so on.
The question states that BUREAK is coded as PZVIFY.
We need to identify how the original letters are transformed into the coded letters.
The rule involves reversing the word and then replacing each letter with its opposite in the alphabet.
The original word is BUREAK.
Reversing the order of its letters gives:
BUREAK β KAERUB
In the opposite-letter coding system, the alphabetical positions of two corresponding letters add up to 27.
The rule is:
\(\text{Opposite position} = 27 - \text{Original position}\)
Applying this rule to KAERUB:
Combining the opposite letters gives PZVIFY.
KAERUB β PZVIFY
This matches the given code and confirms the coding rule.
First, reverse the order of the letters in CASPTL.
CASPTL β LTPSAC
Now replace each letter in LTPSAC with its opposite in the English alphabet.
The opposite letters obtained are O, G, K, H, Z, and X.
Combining them in the same order gives:
LTPSAC β OGKHZX
Therefore, CASPTL is coded as OGKHZX.
For the given example:
BUREAK β KAERUB β PZVIFY
For the required word:
CASPTL β LTPSAC β OGKHZX
Both words follow the same two-step coding rule. Therefore, the correct answer is option D.
Correct Option: D) OGKHZX
The coding rule involves reversing the given word and replacing each letter with its opposite in the English alphabet. Reversing CASPTL gives LTPSAC. Replacing L, T, P, S, A, and C with their opposite letters gives O, G, K, H, Z, and X respectively. Therefore, CASPTL is coded as OGKHZX, making option D correct.
The question asks for the location of the Ajanta Caves. This is a factual question related to Indian history and geography, specifically ancient Indian art and architecture. To answer this, one needs to recall the geographical placement of this famous UNESCO World Heritage site.
Correct Option: D) Maharashtra β The Ajanta Caves are a series of 30 rock-cut Buddhist cave monuments dating from the 2nd century BCE to about 480 CE. They are located in the Aurangabad district of Maharashtra, India, and are a UNESCO World Heritage Site renowned for their exquisite paintings and sculptures.
This is an analogy question where we need to find the relationship between the first pair of words and apply the same relationship to the second pair to find the missing word.
D) Head
A 'Cap' is worn on the 'Head' in the same way a 'Glove' is worn on the 'Hand'. Both are items of clothing designed to cover and protect specific body parts.
Rohan can travel from Delhi to Kanyakumari in 30 h. If he reduces his speed by \( \frac{1}{15} \) th, he will go 10 km less in the same time. His speed is:
This problem involves concepts of speed, distance, and time. We are given the original time taken and a condition where a reduction in speed leads to a shorter distance covered in the same time. We can set up equations based on the formula \(\text{Distance} = \text{Speed} \times \text{Time}\) and solve for the unknown speed.
Let the original speed of Rohan be \(S\) km/h and the total distance from Delhi to Kanyakumari be \(D\) km.
We are given that Rohan can travel from Delhi to Kanyakumari in 30 hours. So, using the formula \(\text{Distance} = \text{Speed} \times \text{Time}\), we have:
\[ D = S \times 30 \quad \text{(Equation 1)} \]If he reduces his speed by \(\frac{1}{15}\)th, his new speed will be:
\[ S' = S - \frac{1}{15}S = S \left(1 - \frac{1}{15}\right) = S \left(\frac{15-1}{15}\right) = \frac{14}{15}S \]In the same time (30 hours), he will go 10 km less. So, the new distance covered will be \(D - 10\) km.
Using the new speed and new distance for the same time, we get:
\[ D - 10 = S' \times 30 \]\[ D - 10 = \left(\frac{14}{15}S\right) \times 30 \]\[ D - 10 = 14S \times \frac{30}{15} \]\[ D - 10 = 14S \times 2 \]\[ D - 10 = 28S \quad \text{(Equation 2)} \]Now we have a system of two equations:
Substitute Equation 1 into Equation 2:
\[ 30S - 10 = 28S \]Solve for \(S\):
\[ 30S - 28S = 10 \]\[ 2S = 10 \]\[ S = \frac{10}{2} \]\[ S = 5 \text{ km/h} \]Thus, Rohan's original speed is 5 km/h.
C) 5 km/h is the correct speed calculated from the given conditions.
This problem involves the properties of similar triangles. When two triangles are similar, the ratio of their areas is equal to the square of the ratio of their corresponding sides. We are given the lengths of corresponding sides BC and EF, and we need to find the ratio of the areas of \(\Delta ABC\) and \(\Delta DEF\).
C) 25 : 16 is the correct ratio of the areas, as calculated by squaring the ratio of the corresponding sides.
The question asks to identify the oldest nuclear research reactor in India. This requires knowledge of the history and establishment dates of India's prominent research reactors.
Apsara is indeed India's first nuclear research reactor. It was commissioned on August 4, 1956, at the Bhabha Atomic Research Centre (BARC) in Trombay, Mumbai. It was a pool-type reactor that used enriched uranium as fuel and light water as both moderator and coolant. Its establishment marked a significant milestone in India's nuclear energy program.
To find the shortest student, we need to establish the relative heights of all students based on the given statements. We will create a height order for the students by combining the information from each statement.
Statement (ii): Q and R are lighter than U but taller than P.
This gives us a height relation: \(Q > P\) and \(R > P\).
Statement (iii): S is taller than Q and heavier than R.
This gives us a height relation: \(S > Q\).
Combining with step 1: \(S > Q > P\) and \(R > P\).
Statement (v): U is taller than S.
This gives us a height relation: \(U > S\).
Combining with step 2: \(U > S > Q > P\) and \(R > P\).
Statement (vii): P is taller than T.
This gives us a height relation: \(P > T\).
Now, let's combine all height relations established so far:
Putting it all together, we get the height order: \(U > S > Q > P > T\).
The position of R is \(R > P\), but its exact position relative to Q, S, U, and T cannot be definitively determined beyond that. However, for finding the shortest person, we only need to identify the one at the very end of the 'taller than' chain.
From the combined order \(U > S > Q > P > T\), T is the shortest.
C) T β Based on the step-by-step analysis, the height order established is \(U > S > Q > P > T\). Therefore, T is the shortest among the students.
A) P β P is taller than T, so P is not the shortest.
B) R β R is taller than P (\(R > P\)). Since P is taller than T, R must also be taller than T. Thus, R is not the shortest.
D) Q β Q is taller than P (\(Q > P\)), and P is taller than T. Therefore, Q is taller than T, meaning Q is not the shortest.
The question asks to identify the neighboring country separated from India by the Palk Strait and the Gulf of Mannar. This requires knowledge of the geographical location of India's neighbors and their maritime boundaries.
A) Sri Lanka β Sri Lanka is an island nation located to the southeast of India, separated by the Palk Strait and the Gulf of Mannar. This is a well-known geographical fact.