This question tests knowledge about the classification of Public Sector Undertakings (PSUs) in India. PSUs are categorized based on their financial performance, operational autonomy, and other criteria into Maharatna, Navratna, and Miniratna categories. Identifying the correct category for Bharat Heavy Electricals Limited (BHEL) requires knowing its status as per government classifications.
Correct Option: C) Maharatna
Bharat Heavy Electricals Limited (BHEL) is a Maharatna company. This status was conferred upon it in 2013, recognizing its significant financial performance, large-scale operations, and strategic importance to the Indian economy. Maharatna companies have the highest degree of financial and operational autonomy among PSUs.
The question asks to identify the fluid matrix of blood in which cellular components like RBCs, WBCs, and platelets are suspended. This requires knowledge of the basic composition of blood.
Correct Option: A) Plasma is the fluid matrix of blood in which red blood cells (RBCs), white blood cells (WBCs), and platelets are suspended. It contains water, proteins, salts, hormones, and nutrients.
The question asks to identify the production activity that is the largest emitter of COâ‚‚. We need to compare the COâ‚‚ emissions from textile production, crop production, meat production, and thermal power production.
D) Thermal power production is the largest emitter of COâ‚‚. The burning of fossil fuels (coal, oil, natural gas) in thermal power plants to generate electricity is the primary source of anthropogenic COâ‚‚ emissions globally.
The question asks to identify the name of a specific scheme launched in March 2016 aimed at improving national highways by eliminating railway level crossings, constructing new bridges, and renovating old ones. This requires knowledge of major government infrastructure projects in India.
B) Setu-Bharatam Project — This project was launched by the Ministry of Road Transport and Highways in March 2016. Its primary objective was to ensure a 'railway level crossing free' National Highway network by 2019, by constructing 208 new Road Over Bridges (ROBs) and Road Under Bridges (RUBs), and to rehabilitate/reconstruct about 1500 old and dilapidated bridges on National Highways. The name 'Setu' means bridge, directly relating to the project's goals.
This problem involves analyzing a statement and deriving logical conclusions based on the principles of deductive reasoning. We need to determine which conclusions necessarily follow from the given statement, even if the statement contradicts common knowledge.
A) Both conclusions 1 and 2 follow. As explained above, "Most students know English" implies that there are students who know English (Conclusion 1) and also implies that there are students who do not know English (Conclusion 2).
The question asks to identify the reign period of Ghiyas-ud-din Balban, a prominent Sultanate ruler of Delhi. This requires knowledge of the chronology of the Delhi Sultanate.
D) 1266-1287 is the correct period during which Ghiyas-ud-din Balban ruled the Delhi Sultanate.
To find the percentage of candidates who passed, we need to divide the number of candidates who passed by the total number of candidates who appeared for the examination, and then multiply the result by 100.
The formula for percentage is:
\[ \text{Percentage} = \left( \frac{\text{Number of passed candidates}}{\text{Total number of candidates}} \right) \times 100 \]Correct Option: A) 90% is the correct percentage of candidates who passed the examination.
The question asks to identify the most thickly populated state in India, excluding Union Territories, based on the 2011 census data. This requires knowledge of population density figures from the 2011 census.
Correct Option: D) Bihar had the highest population density among the states listed in the options, with 1,106 persons per square kilometer as per the 2011 census.
This is an analogy question where we need to find the relationship between the first pair of words and apply the same relationship to the third word to find the fourth word.
Correct Option: D) Iron. A blacksmith is a craftsman who works with iron (or other metals) by heating it and then shaping it with tools such as a hammer, anvil, and chisel. Therefore, iron is the primary material a blacksmith uses, just as gold is for a goldsmith.
The square root of \(\frac{\left(3\frac{1}{4}\right)^4-\left(4\frac{1}{3}\right)^4}{\left(3\frac{1}{4}\right)^2-\left(4\frac{1}{3}\right)^2}\) is:
1\( \frac{1}{12} \)
5 \( \frac{5}{12} \)
1 \( \frac{1}{7} \)
7 \( \frac{7}{12} \)
The problem asks for the square root of a given algebraic expression. The expression involves terms raised to the power of 4 and 2. We can simplify the expression using the algebraic identity \(a^2 - b^2 = (a-b)(a+b)\) and then substitute the given mixed fractions.
Let the given expression be \(E\). We need to find \(\sqrt{E}\).
The expression is:
\[ E = \frac{\left(3\frac{1}{4}\right)^4-\left(4\frac{1}{3}\right)^4}{\left(3\frac{1}{4}\right)^2-\left(4\frac{1}{3}\right)^2} \]Let \(a = 3\frac{1}{4}\) and \(b = 4\frac{1}{3}\). The expression becomes:
\[ E = \frac{a^4 - b^4}{a^2 - b^2} \]Apply the difference of squares identity \(x^2 - y^2 = (x-y)(x+y)\) to the numerator. Here, \(x = a^2\) and \(y = b^2\).
\[ a^4 - b^4 = (a^2)^2 - (b^2)^2 = (a^2 - b^2)(a^2 + b^2) \]Substitute this back into the expression for \(E\):
\[ E = \frac{(a^2 - b^2)(a^2 + b^2)}{a^2 - b^2} \]Assuming \(a^2 - b^2 \neq 0\), we can cancel out the term \((a^2 - b^2)\) from the numerator and denominator.
Note that \(a = 3\frac{1}{4}\) and \(b = 4\frac{1}{3}\). Since \(a \neq b\), \(a^2 \neq b^2\), so \(a^2 - b^2 \neq 0\).
So, the expression simplifies to:
\[ E = a^2 + b^2 \]Now, we need to calculate \(a^2 + b^2\).
First, convert the mixed fractions to improper fractions:
\[ a = 3\frac{1}{4} = \frac{3 \times 4 + 1}{4} = \frac{13}{4} \]\[ b = 4\frac{1}{3} = \frac{4 \times 3 + 1}{3} = \frac{13}{3} \]Calculate \(a^2\) and \(b^2\):
\[ a^2 = \left(\frac{13}{4}\right)^2 = \frac{13^2}{4^2} = \frac{169}{16} \]\[ b^2 = \left(\frac{13}{3}\right)^2 = \frac{13^2}{3^2} = \frac{169}{9} \]Now, find \(E = a^2 + b^2\):
\[ E = \frac{169}{16} + \frac{169}{9} \]Factor out 169:
\[ E = 169 \left(\frac{1}{16} + \frac{1}{9}\right) \]Add the fractions inside the parenthesis:
\[ \frac{1}{16} + \frac{1}{9} = \frac{9 \times 1 + 16 \times 1}{16 \times 9} = \frac{9 + 16}{144} = \frac{25}{144} \]Substitute this back into the expression for \(E\):
\[ E = 169 \times \frac{25}{144} \]The problem asks for the square root of \(E\), which is \(\sqrt{E}\):
\[ \sqrt{E} = \sqrt{169 \times \frac{25}{144}} \]\[ \sqrt{E} = \sqrt{169} \times \sqrt{\frac{25}{144}} \]\[ \sqrt{E} = 13 \times \frac{\sqrt{25}}{\sqrt{144}} \]\[ \sqrt{E} = 13 \times \frac{5}{12} \]\[ \sqrt{E} = \frac{13 \times 5}{12} = \frac{65}{12} \]Convert the improper fraction \(\frac{65}{12}\) back to a mixed fraction:
Divide 65 by 12:
\(65 = 12 \times 5 + 5\)
So, \[\frac{65}{12} = 5\frac{5}{12}\].
Correct Option: B) 5 \( \frac{5}{12} \)