The question asks for an alternative name for Jog Falls, one of India's highest waterfalls. This requires knowledge of geographical facts about India's waterfalls.
Correct Option: C) Jog Falls is also widely known as Gersoppa Falls. It is one of the most spectacular waterfalls in India, formed by the Sharavathi River.
The question asks to identify the type of forest where bamboo, birch, sal, spruce, and sheesham trees can be found. This requires knowledge of the characteristic tree species associated with different forest biomes.
A) temperate deciduous. While sal and sheesham are typically found in tropical/subtropical deciduous forests, and spruce in coniferous forests, the grouping of these diverse species (bamboo, birch, sal, spruce, sheesham) points towards a mixed forest type that encompasses characteristics of temperate regions. Temperate deciduous forests, or mixed forests within temperate zones, can host a variety of species, including deciduous trees like birch, sal, and sheesham, and sometimes coniferous trees like spruce, especially in transition zones. Bamboo also grows in various climates, including temperate ones. This option provides the best fit for the diverse list of trees, emphasizing the deciduous nature of several key species.
The question asks to identify the correct endpoints of the East-West Corridor, which is a part of the National Highway Development Project (NHDP) in India. This requires knowledge of the major corridors under NHDP.
Correct Option: A) Silchar to Porbandar is the correct pair of endpoints for the East-West Corridor under the National Highway Development Project. This corridor connects Silchar in Assam (East) to Porbandar in Gujarat (West).
Kosal, Anga, Kashi and Vajji were all:
conquered by King Ajatshatru
part of 16 Mahajanapadas
ruled by King Harshvardhan in 6th century AD
conquered by King Jaichand
The question asks to identify the common characteristic of Kosal, Anga, Kashi, and Vajji. This requires knowledge of ancient Indian history, specifically the political divisions during the 6th century BCE.
B) part of 16 Mahajanapadas
Kosal, Anga, Kashi, and Vajji were four of the sixteen powerful kingdoms or republics known as Mahajanapadas that flourished in ancient India around the 6th century BCE. These political entities played a crucial role in shaping the early history of India.
To solve this letter-cluster series, we need to identify the pattern of change for each letter's position across the given terms. We will analyze the progression of the first, second, third, and fourth letters independently.
Correct Option: C) GMDV
If the mean of \( \frac{x}{2} \), x, \( \frac{x}{3} \), \( \frac{x}{4} \), and \( \frac{x}{6} \) is 6, then value of x will be:
The problem asks us to find the value of \(x\) given the mean of five terms. The mean of a set of numbers is calculated by summing all the numbers and then dividing by the count of the numbers. We will set up an equation using this definition and solve for \(x\).
\[ \text{Mean} = \frac{\text{Sum of terms}}{\text{Number of terms}} \]
\[ 6 = \frac{\frac{x}{2} + x + \frac{x}{3} + \frac{x}{4} + \frac{x}{6}}{5} \]
\[ 6 \times 5 = \frac{x}{2} + x + \frac{x}{3} + \frac{x}{4} + \frac{x}{6} \]
\[ 30 = \frac{x}{2} + x + \frac{x}{3} + \frac{x}{4} + \frac{x}{6} \]
\[ 30 = \frac{6x}{12} + \frac{12x}{12} + \frac{4x}{12} + \frac{3x}{12} + \frac{2x}{12} \]
\[ 30 = \frac{6x + 12x + 4x + 3x + 2x}{12} \]
\[ 30 = \frac{27x}{12} \]
\[ 30 = \frac{9x}{4} \]
\[ 30 \times 4 = 9x \]
\[ 120 = 9x \]
\[ x = \frac{120}{9} \]
\[ x = \frac{40}{3} \]
B) \( \frac{40}{3} \) is the correct value of \(x\) obtained from the calculations.
The question asks about the administrative body responsible for the Pulitzer Awards. To answer this, one needs to recall the history and organizational structure behind these prestigious awards.
Therefore, the Columbia University in New York is the institution that administers the Pulitzer Awards.
C) The Columbia University, New York administers the Pulitzer Awards, as stipulated in the will of Joseph Pulitzer.
A sum of money at simple interest doubles itself in 4 years 4 months. In how much time will it triple itself?
8 \( \frac{1}{3} \) years
8 years
3 \( \frac{1}{8} \) years
8 \( \frac{2}{3} \) years
This problem involves simple interest. We need to find the rate of interest first, using the information that the sum doubles in a given time. Then, we will use this rate to calculate the time it takes for the sum to triple.
The given time is 4 years 4 months. To convert months to years, divide by 12.
\[ 4 \text{ months} = \frac{4}{12} \text{ years} = \frac{1}{3} \text{ years} \]So, the total time \( T_1 \) is:
\[ T_1 = 4 + \frac{1}{3} = \frac{12+1}{3} = \frac{13}{3} \text{ years} \]Let the principal amount be \( P \). If the sum doubles, the amount \( A_1 \) becomes \( 2P \).
The simple interest \( \text{SI}_1 \) earned is \( A_1 - P = 2P - P = P \).
The formula for simple interest is \( \text{SI} = \frac{P \times R \times T}{100} \), where \( R \) is the rate of interest per annum.
Substitute the values for the first case:
\[ P = \frac{P \times R \times \frac{13}{3}}{100} \]Divide both sides by \( P \) (assuming \( P \neq 0 \)):
\[ 1 = \frac{R \times 13}{300} \]Solve for \( R \):
\[ R = \frac{300}{13} \% \]Now, we want the sum to triple. So, the amount \( A_2 \) will be \( 3P \).
The simple interest \( \text{SI}_2 \) earned will be \( A_2 - P = 3P - P = 2P \).
Using the simple interest formula again with \( \text{SI}_2 = 2P \), the rate \( R = \frac{300}{13} \% \), and let the new time be \( T_2 \):
\[ 2P = \frac{P \times \frac{300}{13} \times T_2}{100} \]Divide both sides by \( P \):
\[ 2 = \frac{300 \times T_2}{13 \times 100} \]Simplify the right side:
\[ 2 = \frac{3 \times T_2}{13} \]Solve for \( T_2 \):
\[ T_2 = \frac{2 \times 13}{3} = \frac{26}{3} \text{ years} \]Convert the fractional part of the years into months:
\[ \frac{26}{3} \text{ years} = 8 \frac{2}{3} \text{ years} \]To convert \( \frac{2}{3} \) years into months:
\[ \frac{2}{3} \times 12 \text{ months} = 8 \text{ months} \]So, the time taken is 8 years 8 months.
D) 8 \( \frac{2}{3} \) years is the correct answer. This matches our calculated time of \( \frac{26}{3} \) years, which is 8 years and 8 months.
This problem requires us to substitute the given symbol transformations into the expression and then evaluate it following the order of operations (BODMAS/PEMDAS).
The original expression is \(24 + 6 / 2 - 9 \times 4\).
Applying the transformations:
So, the new expression is \(24 / 6 - 2 \times 9 + 4\).
First, perform division and multiplication from left to right.
Division: \(24 / 6 = 4\)
The expression becomes \(4 - 2 \times 9 + 4\).
Multiplication: \(2 \times 9 = 18\)
The expression becomes \(4 - 18 + 4\).
Next, perform addition and subtraction from left to right.
Subtraction: \(4 - 18 = -14\)
The expression becomes \(-14 + 4\).
Addition: \(-14 + 4 = -10\)
The value of the expression is \(-10\).
C) -10 — After correctly substituting the symbols and applying the order of operations, the value of the expression is found to be -10.
To answer this question, we need to understand the basic classification of rocks, specifically distinguishing between igneous, sedimentary, and metamorphic rocks. Igneous rocks are formed from the cooling and solidification of molten magma or lava. Sedimentary rocks are formed from the accumulation and compaction of sediments. Metamorphic rocks are formed from existing rocks that are subjected to heat, pressure, or chemical alteration.
Correct Option: C) Dolomite