A train covers a distance of 12 km in 25 minutes. If its speed is decreased by 5 km/hr, then the time (in minutes) taken by it to cover the same distance will be:
30 \( \frac{3}{119} \)
30 \( \frac{3}{119} \)
30 \( \frac{32}{119} \)
30 \( \frac{30}{119} \)
The value of sin 15° sin 30° sin 75° is:
\(\frac{1}{2\sqrt{2}}\)
\(\frac{1}{8}\)
\(\frac{3}{2}\)
\(\frac{1}{4}\)
If a = 2b = 3c and a + b + c = 121 then \(\sqrt{a^2+b^2+c^2}\) is: