If 6(sec²59° − cot²31°) + \( \frac{2}{3} \)sin90° − 3tan²56° y tan²34° = \( \frac{y}{3} \), then the value of y is:
Simplify.
\(\frac{6.25+\frac{5}{7}\times28-5}{\frac{3}{4}\times(15.8-3.4)+5\times2.39}\)
Study the given pattern carefully and select the number that can replace the question mark (?) in it.
Name the 17th zone of the Indian Railways, added in December 2010.
Simplify.
\(\frac{46+\frac{3}{4}\times32-6}{37-\frac{3}{4}\times(34-6)}\)