If 6(sec²59° − cot²31°) + \( \frac{2}{3} \)sin90° − 3tan²56° y tan²34° = \( \frac{y}{3} \), then the value of y is:
Simplify.
\(\frac{6.25+\frac{5}{7}\times28-5}{\frac{3}{4}\times(15.8-3.4)+5\times2.39}\)
Study the given pattern carefully and select the number that can replace the question mark (?) in it.
Name the recently added 17th zone of the Indian Railway.
Konkan Railway
Delhi Metro
Kolkata Metro
East Central Railway
Simplify.
\(\frac{46+\frac{3}{4}\times32-6}{37-\frac{3}{4}\times(34-6)}\)