The question asks to identify the state that secured the top position in the Khelo India Youth Games (KIYG) held in 2020. This requires knowledge of the results of that specific event.
Correct Option: B) Maharashtra
The problem is a coding-decoding question. We need to identify the pattern used to transform the given words into their coded forms and then apply the same pattern to the word "EXTREME".
Let's write down the letters and their corresponding coded letters:
This doesn't immediately look like a simple shift cipher. Let's consider the reverse alphabetical order or position from the end of the alphabet.
Let's re-examine the pattern. It seems to be a combination of forward and reverse shifts, or a specific mapping.
Consider the concept of "opposite" letters where the sum of their positions from the start and end of the alphabet is 27 (e.g., A=1, Z=26; A+Z = 1+26=27). Let's check this for the first and last letters:
Now, let's look at the middle letters. The word SUCCESS has 7 letters. The middle letter is the 4th 'C'.
The pattern is: Opposite, +1, Opposite, +1, Opposite, +1, Opposite. Let's verify this with the second example.
The word LOVELY has 6 letters.
The pattern is consistently: Opposite, +1, Opposite, +1, Opposite, +1.
The word EXTREME has 7 letters. The pattern will be: Opposite, +1, Opposite, +1, Opposite, +1, Opposite.
So, EXTREME will be coded as VYGSVNV.
C) VYGSVNV is the correct code derived from applying the established pattern of (Opposite, +1, Opposite, +1, Opposite, +1, Opposite) to the letters of EXTREME.
The question asks to identify the odd one out from the given options. This requires classifying each option into a broader biological category and then finding the one that doesn't fit the pattern established by the others.
C) Man is the odd one out because 'Reptile', 'Mammal', and 'Avian' are broad biological classes of animals, whereas 'Man' refers to a specific species within the class Mammalia. Thus, 'Man' is a sub-category of one of the other options, not a parallel category.
If sin θ + cos θ = \(\sqrt{3}\) cos(90 - θ) then tan θ = ?
\(\sqrt{2-1}\)
\(\frac{1}{\sqrt{3}-1}\)
\(\frac{1}{\sqrt{2}-1}\)
\(\sqrt{3}-1\)
The problem requires us to find the value of \(\tan \theta\) given an equation involving \(\sin \theta\) and \(\cos \theta\). We will use trigonometric identities to simplify the given equation and then solve for \(\tan \theta\).
Simplify the right-hand side of the equation:
The given equation is \(\sin \theta + \cos \theta = \sqrt{3} \cos(90 - \theta)\).
We know the trigonometric identity \(\cos(90 - \theta) = \sin \theta\).
Substitute this into the equation:
Rearrange the terms to isolate \(\sin \theta\) and \(\cos \theta\):
Move all terms involving \(\sin \theta\) to one side and \(\cos \theta\) to the other side:
Solve for \(\tan \theta\):
Recall that \(\tan \theta = \frac{\sin \theta}{\cos \theta}\). To get this form, divide both sides of the equation by \(\cos \theta\) (assuming \(\cos \theta \neq 0\)):
Rationalize the denominator (optional, but good practice for simplification):
Multiply the numerator and denominator by the conjugate of the denominator, which is \(\sqrt{3} + 1\):
Comparing this result with the given options, option B matches the unrationalized form.
Correct Option: B) \(\frac{1}{\sqrt{3}-1}\)
The question asks for the approximate concentration of carbon dioxide in the Earth's atmosphere. This is a factual recall question related to environmental science and atmospheric composition. We need to identify the correct percentage from the given options.
Correct Option: B) 0.03%
The concentration of carbon dioxide in the Earth's atmosphere is approximately 0.03% to 0.04%. Option B, 0.03%, is the most accurate approximation among the choices provided. While the exact concentration fluctuates and has been rising, 0.03% is a commonly accepted figure for general knowledge questions.
The value of 5 \(\frac{7}{9}\div4\frac{1}{3}\times6\frac{9}{14}+\frac{7}{9}\)× 18 is:
22 \( \frac{6}{7} \)
21 \( \frac{6}{8} \)
22 \( \frac{7}{6} \)
21 \( \frac{8}{6} \)
To solve this problem, we need to follow the order of operations (BODMAS/PEMDAS). First, convert all mixed fractions to improper fractions. Then perform division, multiplication, and finally addition, followed by the final multiplication.
Convert mixed fractions to improper fractions:
\[5 \frac{7}{9} = \frac{(5 \times 9) + 7}{9} = \frac{45 + 7}{9} = \frac{52}{9}\]
\[4 \frac{1}{3} = \frac{(4 \times 3) + 1}{3} = \frac{12 + 1}{3} = \frac{13}{3}\]
\[6 \frac{9}{14} = \frac{(6 \times 14) + 9}{14} = \frac{84 + 9}{14} = \frac{93}{14}\]
Substitute these into the expression:
\[ \frac{52}{9} \div \frac{13}{3} \times \frac{93}{14} + \frac{7}{9} \times 18 \]
Perform the division:
\[ \frac{52}{9} \div \frac{13}{3} = \frac{52}{9} \times \frac{3}{13} \]
Cancel common factors:
\[ \frac{\cancel{52}^{4}}{\cancel{9}^{3}} \times \frac{\cancel{3}^{1}}{\cancel{13}^{1}} = \frac{4}{3} \]
Perform the multiplication with the result of the division:
\[ \frac{4}{3} \times \frac{93}{14} \]
Cancel common factors:
\[ \frac{\cancel{4}^{2}}{\cancel{3}^{1}} \times \frac{\cancel{93}^{31}}{\cancel{14}^{7}} = \frac{2 \times 31}{1 \times 7} = \frac{62}{7} \]
Perform the multiplication outside the parentheses:
\[ \frac{7}{9} \times 18 \]
Cancel common factors:
\[ \frac{7}{\cancel{9}^{1}} \times \cancel{18}^{2} = 7 \times 2 = 14 \]
Combine the results with addition:
The expression now becomes:
\[ \frac{62}{7} + 14 \]
To add, find a common denominator:
\[ \frac{62}{7} + \frac{14 \times 7}{7} = \frac{62}{7} + \frac{98}{7} = \frac{62 + 98}{7} = \frac{160}{7} \]
Convert the improper fraction to a mixed fraction:
\[ \frac{160}{7} \]
Divide 160 by 7:
\(160 \div 7 = 22\) with a remainder of \(6\).
So, the mixed fraction is \(22 \frac{6}{7}\).
A) \(22 \frac{6}{7}\) is the correct answer as derived from the step-by-step calculation.
To solve this problem, we need to perform addition and subtraction of decimal numbers. It's best to group the positive numbers together and the negative numbers together, then perform the final subtraction.
The expression can be written as:
\[ 42.425 + 6.526 - 15.31 + 0.098 \]\[ = (42.425 + 6.526 + 0.098) - 15.31 \]\[ = 49.049 - 15.31 \]\[ = 33.739 \]B) 33.739 is the correct result obtained after performing the addition and subtraction of the given decimal numbers.
The question asks about a plantation method specifically designed to prevent soil erosion in desert environments. We need to identify the technique that uses plants to combat wind erosion, which is prevalent in deserts.
Correct Option: C) Shelter belts are rows of trees or shrubs planted to protect fields and prevent soil erosion by reducing wind speed. This method is particularly effective in desert areas where wind erosion is a major concern.
The given series consists of terms like "NumberLetter". We need to identify the pattern in both the numbers and the letters separately to find the next term.
Correct Option: D) 31J
The question asks to identify which of the given options is commonly known as "Alfalfa." This requires knowledge of common names for plants or other biological terms.
Correct Option: A) Sativa. Alfalfa is the common name for the plant Medicago sativa. The term "sativa" is part of its scientific name, making it the correct answer.