In what time will ₹3,200 invested at 10% per annum compounded quarterly become ₹3,362?
2 years
\( \frac{1}{2} \) year
2 \( \frac{1}{2} \) years
\( \frac{1}{4} \) year
In the given figure, AB is the diameter of the circle. AP is a tangent to circle at A. Extended BC meets the tangent at P. ∠AOC = 36°. Find ∠BPQ.