This is an analogy question. We need to identify the relationship between the first pair of words (Flowerpot : Mud) and then apply the same relationship to the third word (Candle) to find the missing fourth word.
Correct Option: C) Wax — A candle is made from wax, just as a flowerpot is made from mud.
The question asks to identify the sport associated with the Begum Hazrat Mahal Cup. This requires knowledge of famous sports trophies and the sports they are linked to.
The Begum Hazrat Mahal Cup is a national-level football tournament in India. It is named after Begum Hazrat Mahal, a prominent figure in the Indian Rebellion of 1857.
D) Football — The Begum Hazrat Mahal Cup is a national football tournament in India, specifically for women's football.
To solve this problem, we first need to find the Cost Price (CP) of the item using the given Selling Price (SP) and profit percentage. Once the CP is known, we can calculate the loss percentage if the item is sold at a different SP.
Given:
The formula to find CP when SP and profit percentage are given is:
\[ \text{CP} = \frac{\text{SP}_1}{1 + \frac{\text{P}\%}{100}} \]Substitute the given values:
\[ \text{CP} = \frac{649}{1 + \frac{18}{100}} = \frac{649}{1 + 0.18} = \frac{649}{1.18} \]Calculate the CP:
\[ \text{CP} = 550 \]So, the Cost Price of the item is Rs 550.
Given the new Selling Price (\(\text{SP}_2\)) = Rs 418.
Since \(\text{SP}_2\) (Rs 418) is less than CP (Rs 550), there is a loss.
First, calculate the Loss amount:
\[ \text{Loss} = \text{CP} - \text{SP}_2 = 550 - 418 = 132 \]Now, calculate the Loss percentage (\(\text{L}\%\)):
\[ \text{L}\% = \frac{\text{Loss}}{\text{CP}} \times 100 \]Substitute the values:
\[ \text{L}\% = \frac{132}{550} \times 100 \]Simplify the expression:
\[ \text{L}\% = \frac{13200}{550} = \frac{1320}{55} = 24 \]So, the loss percentage is 24%.
Correct Option: B) 24
The cost price of the item is Rs 550. If it is sold for Rs 418, the loss is Rs 132. The loss percentage is \((132/550) \times 100 = 24\%\).
If a force (F) is acting in the direction of displacement (s) on an object, what will be the equation of work (W)?
The question asks for the equation of work (W) when a force (F) acts in the direction of displacement (s). This is a fundamental concept in physics, specifically in mechanics.
B) \(F \times s\) — This is the correct definition of work done when a force acts in the direction of displacement.
This is a blood relation question. To solve such problems, it's best to break down the relationship step-by-step, starting from the last part of the description and working backward to identify the exact relationship between the two individuals.
Correct Option: C) Her cousin
The problem asks us to find a distance that satisfies given speed and time constraints for two individuals, Ghanshyam and Sutirtha. We are given ranges for their fixed speeds and the time each took to complete the journey. We need to check which of the given options for distance fits these conditions.
D) 252 km
This distance satisfies both conditions:
The chemical formula of Ammonium Sulphate is ____
To determine the correct chemical formula for Ammonium Sulphate, we need to understand the charges of the individual ions involved and apply the principle of charge neutrality for ionic compounds.
Correct Option: C) (NH 4 ) 2 SO 4 — This formula correctly represents the combination of two ammonium ions \(\text{(NH}_4^+)\) and one sulphate ion \(\text{(SO}_4^{2-})\) to achieve charge neutrality.
This question asks about the visual appearance of rust on iron. Rusting is a common chemical process (oxidation) that occurs when iron is exposed to oxygen and moisture. Understanding the product of this reaction will help identify its characteristic color.
Correct Option: D) Red brown powder is coated.
The sum of \( \frac{7}{11} \) and \( \frac{11}{7} \) is ________
\( \frac{170}{77} \)
\( \frac{18}{77} \)
\( \frac{18}{18} \)
\( \frac{77}{18} \)
To find the sum of two fractions with different denominators, we first need to find a common denominator, which is usually the Least Common Multiple (LCM) of the denominators. Then, we convert each fraction to an equivalent fraction with this common denominator and add the numerators.
For the first fraction, \( \frac{7}{11} \):
\[ \frac{7}{11} = \frac{7 \times 7}{11 \times 7} = \frac{49}{77} \]For the second fraction, \( \frac{11}{7} \):
\[ \frac{11}{7} = \frac{11 \times 11}{7 \times 11} = \frac{121}{77} \]Correct Option: A) \( \frac{170}{77} \) is the sum of the given fractions.
This is a blood relation question. We need to trace the relationships step-by-step to identify the person Mahi met.
Correct Option: D) Her husband's uncle