The question asks about a specific appointment made to the Securities and Exchange Board of India (SEBI) on a particular date. This requires knowledge of significant appointments in regulatory bodies, which is a common topic in current affairs for competitive exams.
On November 7, 2017, the government appointed Sanjeev Kaushik, a 1992-batch IAS officer of the Kerala cadre, as a whole-time member of SEBI. This appointment was for a period of three years.
B) Sanjeev Kaushik was indeed appointed as a whole-time member of SEBI on November 7, 2017. He was a 1992-batch IAS officer.
The question asks to identify the Union Minister of Health and Family Welfare as of August 2018. This requires knowledge of the Union Cabinet portfolios during that specific period.
As of August 2018, J. P. Nadda was indeed the Union Minister of Health and Family Welfare in the Government of India.
Correct Option: C) J. P. Nadda was the Union Minister of Health and Family Welfare as of August 2018. He held this portfolio from November 2014 to May 2019.
This problem can be solved by setting up a system of linear equations based on the given information. We need to find the number of students in the first group. Let's assign variables to the number of students in each group and then form equations from the total number of students and the relationship between the two groups.
C) 12 — As calculated, the number of students in the first group is 12.
The problem asks us to determine the days Latika will fill petrol in the following week, given that she fills it every three days and her last fill was on a Wednesday. We need to count forward three days from each petrol fill to find the subsequent dates.
Let's list the days she fills petrol:
The question asks for the days she will fill petrol in the following week. From our sequence, the fills in the following week are Tuesday and Friday. Let's re-check the counting. "Once in three days" means there are 2 days between fills. So, if she fills on Day X, the next fill is on Day X + 3.
Let's interpret "once in three days" as a 2-day gap between fills, meaning the fill happens on the 3rd day from the previous fill. This is a common interpretation in such problems.
So, the fills are on Wednesday, Saturday, Tuesday, Friday, Monday, etc.
The question states: "This week if she puts petrol on a Wednesday, on which of the following days will she fill petrol in the following week?"
Let's assume "this week" starts on a Monday. So, Wednesday is in "this week".
Therefore, in the following week, she will fill petrol on Tuesday and Friday.
B) Tuesday and Friday — As calculated, if she fills on Wednesday, the sequence of fills is Wednesday, Saturday, Tuesday (next week), Friday (next week), Monday (next week), etc. The fills occurring in the following week are Tuesday and Friday.
The problem involves relating the dimensions, volume, and area of a cube and a square. We will set up equations based on the given conditions and solve for the unknown length of the cube's edge.
Let the length of one edge of the cube be \(a\) units.
A cube has 12 edges. The sum of the lengths of the edges of the cube is \(12a\).
Let the side length of the square be \(s\) units.
The perimeter of the square is \(4s\).
According to the first condition, the sum of the lengths of the edges of a cube is equal to one-eighth of the perimeter of a square:
\[ 12a = \frac{1}{8} (4s) \] \[ 12a = \frac{s}{2} \] \[ s = 24a \quad \text{(Equation 1)} \]The numerical value of the volume of the cube is \(V_{\text{cube}} = a^3\).
The numerical value of the area of the square is \(A_{\text{square}} = s^2\).
According to the second condition, the numerical value of the volume of the cube is equal to the numerical value of the area of the square:
\[ a^3 = s^2 \quad \text{(Equation 2)} \]Substitute Equation 1 into Equation 2:
\[ a^3 = (24a)^2 \] \[ a^3 = 24^2 a^2 \] \[ a^3 = 576 a^2 \]To solve for \(a\), we can divide both sides by \(a^2\). Since \(a\) represents a length, \(a \neq 0\).
\[ \frac{a^3}{a^2} = 576 \] \[ a = 576 \]Therefore, the length of one edge of the cube is 576 units.
A) 576 units is the correct answer, as derived from the calculations.
Who among the following bagged the Best Actor award at the 64th National Film Awards held in 2017?
The question asks to identify the recipient of the Best Actor award at the 64th National Film Awards held in 2017. This requires knowledge of major awards and their winners in Indian cinema, a common topic in general awareness sections of competitive exams.
C) Akshay Kumar was awarded the Best Actor at the 64th National Film Awards for his role in the film 'Rustom'.
The question asks to identify the city that launched India's first helicopter-taxi service. This is a factual question related to current affairs and infrastructure development in Indian cities. Recalling major urban initiatives and their locations is key.
Correct Option: D) Bengaluru
Bengaluru launched India's first helicopter-taxi service in March 2018. This service was introduced to provide quick connectivity between Kempegowda International Airport and various parts of the city, starting with Electronic City.
The question asks for the Chief Minister of Telangana as of March 2018. This requires knowledge of the political landscape and leadership at that specific time.
Correct Option: B) K. Chandrashekar Rao
The sales figures of a particular brand of sugar in 3 states over 3 years are given in the below table. The figures are in lakhs of rupees.
| State1 | State2 | State3 | |
| Year1 | 15 | 12 | 9 |
| Year2 | 12 | 14 | 8 |
| Year3 | 14 | 15 | 13 |
What is the percentage difference in sales from year 1 to year 3?
To find the percentage difference in sales from Year 1 to Year 3, we first need to calculate the total sales for Year 1 and Year 3 across all states. Then, we will use the formula for percentage difference, which is \[\frac{\text{Difference}}{\text{Original Value}} \times 100\].
Calculate total sales for Year 1:
Add the sales figures for State 1, State 2, and State 3 in Year 1.
Calculate total sales for Year 3:
Add the sales figures for State 1, State 2, and State 3 in Year 3.
Calculate the difference in sales:
Subtract the total sales of Year 1 from the total sales of Year 3.
Calculate the percentage difference:
The percentage difference is calculated with respect to the sales in Year 1 (the original value).
Correct Option: A) 16.67%
The problem states that Paranjoy secured 272 marks, which is equivalent to 64% of the total marks. We need to find the total marks for the test. This can be solved by setting up a proportion or by using the percentage formula to find the whole when a part and its percentage are known.
Let the total marks of the test be \(T\).
The marks secured (272) represent 64% of the total marks (\(T\)). We can write this as:
\[ 64\% \text{ of } T = 272 \]64% can be written as \(\frac{64}{100}\).
To find \(T\), multiply both sides of the equation by \(\frac{100}{64}\):
\[ T = 272 \times \frac{100}{64} \]We can simplify the fraction or perform the multiplication directly.
Alternatively, simplify the fraction first:
The total marks for the test are 425.
B) 425 is the correct total marks for the test, as calculated.