The task is to evaluate which of the given conclusions logically follow from the provided statement. We need to analyze each conclusion independently based solely on the information given in the statement.
C) Only conclusion I follows. Conclusion I is a direct premise for the statement to be meaningful. The statement discusses the impact on an "innate healing sense," which implies its existence.
The question asks about the Ministry responsible for the Swadesh Darshan Scheme. This requires knowledge of major government schemes and their administering ministries, which is a common topic in competitive exams.
C) Tourism - The Swadesh Darshan Scheme is indeed an initiative of the Ministry of Tourism. It was launched in 2014-15 with the objective of integrated development of theme-based tourist circuits in India.
\( \frac{3}{5} \)th of Sarah’s amount is equal to \( \frac{6}{7} \)th of Priya’s amount. Between them the duo has Rs. 3,570. How much money does Priya have?
To solve this problem, we need to set up equations based on the given information. We are told that a fraction of Sarah's amount is equal to a fraction of Priya's amount, and we also know their total combined amount. We will use these two pieces of information to find the individual amounts.
Let Sarah's amount be \(S\) and Priya's amount be \(P\).
From the first statement, "\( \frac{3}{5} \) th of Sarah’s amount is equal to \( \frac{6}{7} \) th of Priya’s amount", we can write the equation:
\[ \frac{3}{5} S = \frac{6}{7} P \]We can simplify this equation to find the ratio of \(S\) to \(P\):
\[ S = \frac{6}{7} P \times \frac{5}{3} \] \[ S = \frac{6 \times 5}{7 \times 3} P \] \[ S = \frac{30}{21} P \]Simplifying the fraction \( \frac{30}{21} \) by dividing both numerator and denominator by 3:
\[ S = \frac{10}{7} P \]This means that for every 10 units Sarah has, Priya has 7 units. So, the ratio \(S:P = 10:7\).
From the second statement, "Between them the duo has Rs. 3,570", we can write the equation:
\[ S + P = 3570 \]Now we have a system of two equations:
Substitute the expression for \(S\) from equation (a) into equation (b):
\[ \frac{10}{7} P + P = 3570 \]Combine the terms involving \(P\):
\[ \left( \frac{10}{7} + 1 \right) P = 3570 \] \[ \left( \frac{10}{7} + \frac{7}{7} \right) P = 3570 \] \[ \frac{17}{7} P = 3570 \]Solve for \(P\):
\[ P = 3570 \times \frac{7}{17} \]To simplify, divide 3570 by 17:
\[ 3570 \div 17 = 210 \]So,
\[ P = 210 \times 7 \] \[ P = 1470 \]Thus, Priya has Rs. 1,470.
C) Rs. 1,470 is the correct amount Priya has.
A) Rs. 1,540: This would be incorrect. If Priya had Rs. 1,540, then Sarah would have \( \frac{10}{7} \times 1540 = 10 \times 220 = 2200 \). Their total would be \( 1540 + 2200 = 3740 \), which is not Rs. 3,570.
B) Rs. 2,100: This is the amount Sarah has, not Priya. If Priya has Rs. 1,470, then Sarah has \( 3570 - 1470 = 2100 \). This option represents Sarah's amount, not Priya's.
D) Rs. 1,400: This is incorrect. If Priya had Rs. 1,400, then Sarah would have \( \frac{10}{7} \times 1400 = 10 \times 200 = 2000 \). Their total would be \( 1400 + 2000 = 3400 \), which is not Rs. 3,570.
The question asks to identify the type of meristematic tissue found at the base of leaves or internodes. This requires knowledge of the location and function of different types of meristems in plants.
Correct Option: B) Intercalary meristem is present at the base of the leaves or internodes on twigs. This meristem is particularly active in grasses, allowing them to regrow after being cut or grazed.
The problem asks us to decode a word based on a given coding pattern. We need to identify the rule applied to transform "STAPLE" into "RSZOKD" and then apply the same rule to "DIGEST".
Compare the letters of the original word "STAPLE" with the coded word "RSZOKD" letter by letter.
The pattern observed is that each letter in the original word is shifted one position backward in the English alphabet (i.e., replaced by the letter immediately preceding it). For 'A', it wraps around to 'Z'.
Now, we apply the same "minus one" rule to each letter of the word "DIGEST".
Combining the transformed letters, "DIGEST" becomes "CHFDRS".
Correct Option: C) CHFDRS
To find the measure of the greatest angle in a pentagon, we first need to determine the sum of the interior angles of a pentagon. Then, using the given ratio of the angles, we can set up an equation to find the value of each angle and identify the greatest one.
Correct Option: D) 150°
The question asks to identify the odd one out from the given options. We need to find a common characteristic among three options and then identify the one that does not share that characteristic.
B) Neigh — This is the sound made by a horse, whereas Cat, Frog, and Goat are all names of animals. Therefore, "Neigh" is the odd one out.
The question asks to identify the most commonly used indicator in laboratories. We need to evaluate each option based on its prevalence and general utility in chemical experiments.
A) Litmus — Litmus is arguably the most widely recognized and commonly used indicator in laboratories, especially for preliminary tests to determine if a solution is acidic or basic. Its simplicity, low cost, and ease of use make it ubiquitous.
If 3x2 + ax + 12 is perfectly divisible by (x – 3), then the value of ‘a’ is:
This problem can be solved using the Remainder Theorem. The Remainder Theorem states that if a polynomial \(P(x)\) is divided by \((x - c)\), then the remainder is \(P(c)\). If a polynomial is perfectly divisible by \((x - c)\), it means the remainder is 0, so \(P(c) = 0\).
Correct Option: A) -13 is the correct value for 'a'.
This problem can be solved by applying the Law of Conservation of Mass. This fundamental law states that in a closed system, the mass of the reactants must equal the mass of the products. In a chemical reaction, matter is neither created nor destroyed.
The reactants are mercury (\(\text{Hg}\)) and oxygen (\(\text{O}_2\)).
The product is mercuric oxide (\(\text{HgO}\)).
The chemical reaction can be represented as:
\[ 2\text{Hg} + \text{O}_2 \rightarrow 2\text{HgO} \]According to the Law of Conservation of Mass, the total mass of the reactants must be equal to the total mass of the products.
\[ \text{Mass of reactants} = \text{Mass of products} \]Given mass of mercury = \(92.6 \text{ g}\)
Given mass of oxygen = \(7.4 \text{ g}\)
Total mass of reactants = Mass of mercury + Mass of oxygen
\[ \text{Total mass of reactants} = 92.6 \text{ g} + 7.4 \text{ g} = 100 \text{ g} \]Since the mass of reactants equals the mass of products, the mass of mercuric oxide formed will be equal to the total mass of the reactants.
\[ \text{Mass of mercuric oxide} = \text{Total mass of reactants} = 100 \text{ g} \]A) 100 g — Based on the Law of Conservation of Mass, the sum of the masses of mercury and oxygen reacting is \(92.6 \text{ g} + 7.4 \text{ g} = 100 \text{ g}\). Therefore, the mass of the product, mercuric oxide, must also be \(100 \text{ g}\).