The question asks about the state government that first launched the 'Gobar-dhan' scheme. This requires knowledge of the scheme's origin and initial implementation.
B) Haryana was the state where the 'Gobar-dhan' scheme was first launched as a pilot project by the central government.
This question asks us to identify implicit assumptions based on a given statement. We need to analyze each assumption to see if it is a necessary underlying belief for the statement to be made.
B) Only II is implicit. Assumption II is directly supported by the phrasing "instead of 8:00 am," implying a deviation from a regular schedule.
The question asks to identify the group of plants that produces naked seeds. This requires knowledge of the basic characteristics of major plant divisions, particularly how their seeds are enclosed or exposed.
Correct Option: D) Gymnosperms – Gymnosperms are a group of seed-producing plants where the seeds are not enclosed within an ovary. The term "gymnosperm" literally means "naked seed" (from Greek "gymnos" meaning naked and "sperma" meaning seed).
To find the next term in the series, we need to identify the pattern or rule governing the sequence of numbers. This typically involves looking at the differences between consecutive terms.
Analyze the given series: The series is 31, 38, 44, 51.
Calculate the differences between consecutive terms:
Identify the pattern of differences: The differences are 7, 6, 7. This indicates an alternating pattern where the difference is first 7, then 6, then 7 again.
Predict the next difference: Following the alternating pattern (7, 6, 7, ...), the next difference should be 6.
Calculate the next term: Add the predicted difference to the last term in the series.
\(51 + 6 = 57\)
B) 57 is the correct answer because it follows the established alternating pattern of differences (+7, +6, +7, +6).
What is the ratio of the height of an equilateral triangle to its side?
2 : 3
\(\sqrt{3}\) : 2
1 : \(\sqrt{3}\)
4 : 3\(\sqrt{3}\)
To find the ratio of the height of an equilateral triangle to its side, we can use the properties of an equilateral triangle and the Pythagorean theorem. An equilateral triangle has all sides equal and all angles equal to 60 degrees. Drawing an altitude from one vertex to the opposite side bisects that side and forms two congruent right-angled triangles.
Correct Option: B) \(\sqrt{3}\) : 2
\( \frac{3}{12} \) of \(\frac{\left(\frac{2}{5}+\frac{4}{15}\right)}{\left(\frac{2}{5}-\frac{1}{5}\right)}\)=?
\( \frac{5}{7} \)
\( \frac{5}{6} \)
\( \frac{6}{5} \)
\( \frac{2}{6} \)
To solve this problem, we need to simplify the given expression by performing the operations within the parentheses first, following the order of operations (PEMDAS/BODMAS). We will simplify the numerator and the denominator of the fraction separately, then divide them, and finally multiply by the initial fraction.
The numerator is \[\frac{2}{5} + \frac{4}{15}\]. To add these fractions, find a common denominator, which is 15.
\[ \frac{2}{5} + \frac{4}{15} = \frac{2 \times 3}{5 \times 3} + \frac{4}{15} = \frac{6}{15} + \frac{4}{15} = \frac{6+4}{15} = \frac{10}{15} \]The denominator is \[\frac{2}{5} - \frac{1}{5}\]. Since they already have a common denominator, we can subtract directly.
\[ \frac{2}{5} - \frac{1}{5} = \frac{2-1}{5} = \frac{1}{5} \]Now, divide the simplified numerator by the simplified denominator.
\[ \frac{\left(\frac{10}{15}\right)}{\left(\frac{1}{5}\right)} = \frac{10}{15} \div \frac{1}{5} = \frac{10}{15} \times \frac{5}{1} \]Multiply the fractions. We can simplify before multiplying.
\[ \frac{10}{15} \times \frac{5}{1} = \frac{10}{3 \times 5} \times \frac{5}{1} = \frac{10}{3} \]The original expression is \( \frac{3}{12} \) of the result from step 4. "Of" means multiplication.
\[ \frac{3}{12} \times \frac{10}{3} \]Multiply the numerators and denominators, then simplify the resulting fraction.
\[ \frac{3 \times 10}{12 \times 3} = \frac{30}{36} \]To simplify \( \frac{30}{36} \), divide both the numerator and the denominator by their greatest common divisor, which is 6.
\[ \frac{30 \div 6}{36 \div 6} = \frac{5}{6} \]B) \( \frac{5}{6} \) is the correct answer, as derived from the step-by-step calculation.
The given series is an alternating series, meaning it consists of two interleaved sub-series. We need to identify the pattern in each sub-series to find the next term.
Correct Option: C) U
The question asks about the composition of the Electoral College responsible for electing the President of India. Understanding the constitutional provisions related to presidential elections is key to answering this question.
Correct Option: D) Elected members of the Parliament and the State Legislative Assemblies
This option correctly identifies the key components of the Electoral College for the President of India, which includes elected members from both the central legislature (Parliament) and state legislatures (State Legislative Assemblies), along with the Legislative Assemblies of Delhi and Puducherry.
An element of atomic number 16 will belong to the ______ period of the periodic table.
To determine the period of an element in the periodic table, we need to find its electronic configuration. The period number corresponds to the highest principal quantum number (n) or the number of electron shells occupied by electrons.
Correct Option: C) 3 rd
To find the energy consumed in "units", we need to calculate the total energy in kilowatt-hours (kWh). One unit of electrical energy is equivalent to 1 kilowatt-hour. We are given the power of the bulb in watts and the time it is used in hours. We will convert watts to kilowatts and then multiply by the time in hours to get the energy in kWh.
Since 1 kW = 1000 W, we divide the power in watts by 1000.
\[ P \text{ (in kW)} = \frac{100 \text{ W}}{1000} = 0.1 \text{ kW} \]Energy (\(E\)) is calculated as Power (\(P\)) multiplied by Time (\(t\)).
\[ E = P \times t \]\[ E = 0.1 \text{ kW} \times 8 \text{ hours} \]\[ E = 0.8 \text{ kWh} \]One unit of electrical energy is equal to 1 kWh.
\[ \text{Energy in units} = 0.8 \text{ kWh} \times \frac{1 \text{ unit}}{1 \text{ kWh}} = 0.8 \text{ units} \]Correct Option: D) 0.8