The question asks to identify the correct description of Newton's Second Law of Motion. We need to recall the definitions and implications of Newton's three laws of motion and the law of conservation of energy.
D) Relates the force acting on a body to the rate of change of its momentum. This is the precise definition of Newton's Second Law of Motion. As discussed in step 2, the law states that the net force acting on an object is equal to the rate at which its momentum changes.
This problem involves calculating the cumulative depreciation of an asset over several years. Since the depreciation is a fixed percentage annually, it's a compound depreciation problem. We need to find the final value after 4 years and then calculate the total percentage fall from the original price.
Correct Option: A) 34.39
What is the amount of work done by a boy against gravity in which he takes a bicycle weighing 3 kg to a distance of 10 meters on a flat road? (g = 9.8 m/sec2)
The problem asks for the work done against gravity when a boy takes a bicycle on a flat road. Work done against gravity depends on the vertical displacement of the object. We need to determine if there is any vertical displacement in this scenario.
A) 0 J is the correct answer because there is no vertical displacement when moving an object on a flat road, hence no work is done against gravity.
The question asks to identify a vascular plant from the given options. Vascular plants are characterized by the presence of specialized tissues (xylem and phloem) for the transport of water, minerals, and food throughout the plant body. These are also known as tracheophytes.
Correct Option: A) Marsilea
Marsilea is a genus of aquatic ferns, which belong to the group Pteridophyta. Pteridophytes are the first group of terrestrial plants to possess well-differentiated vascular tissues (xylem and phloem) for conduction of water and nutrients. Therefore, Marsilea is a vascular plant.
This is a logical reasoning question based on a statement and conclusions. We need to determine which conclusion(s) can be logically derived directly from the given statement, without making additional assumptions.
Correct Option: A) Only conclusion 1 follows.
The question asks to identify the Indian squash player who first achieved a top 10 ranking in the PSA women's rankings. This requires knowledge of the historical achievements of prominent Indian squash players.
A) Deepika Pallikal Karthik became the first Indian female squash player to break into the top 10 of the Professional Squash Association (PSA) world rankings in December 2012, reaching a career-high ranking of World No. 10. This is a significant milestone in Indian squash history.
This is a direction-based reasoning question. We need to identify the pattern of change in directions provided and then apply the same pattern to find the new name for 'North'. The changes involve a consistent rotation of the cardinal and intercardinal directions.
However, none of the options is 'North-East'. Let's re-examine the rotation. It seems the question implies a shift in the entire compass, not just individual points. Let's consider the shift in terms of positions:
So, the pattern is that every direction is effectively shifted 45 degrees anti-clockwise. To find what 'North' will be called, we need to find the direction that is 45 degrees anti-clockwise from 'North'.
45 degrees anti-clockwise from 'North' is 'North-West'.
D) North-West — Following the established pattern, every direction is shifted 45 degrees anti-clockwise. Applying this shift to 'North', the direction that is 45 degrees anti-clockwise from 'North' is 'North-West'. Therefore, 'North' will be called 'North-West'.
An object of mass 14 kg is placed at a certain height from the ground. If the potential energy of the object is 560 J, then find the height of the object with reference to the ground. (take g = 10 ms-2)
To find the height of the object, we need to use the formula for gravitational potential energy, which relates mass, gravitational acceleration, and height. We are given the potential energy, mass, and the value of gravitational acceleration.
The potential energy (\(PE\)) of an object at a certain height (\(h\)) is given by:
\[ PE = mgh \]To find the height, we can rearrange the formula as:
\[ h = \frac{PE}{mg} \]Now, plug in the values for \(PE\), \(m\), and \(g\):
\[ h = \frac{560 \text{ J}}{(14 \text{ kg}) \times (10 \text{ m/s}^2)} \]B) 4 m — The calculation shows that the height of the object is 4 meters.
The problem presents a series with a number followed by two letters. We need to identify the pattern in the numbers and the letters separately to find the next term.
The numbers in the series are 11, 15. Let's find the difference between them.
\[ 15 - 11 = 4 \]Assuming a consistent pattern, the next number should be \(15 + 4 = 19\).
The first letters in the series are K, O. Let's find their positions in the English alphabet.
The difference in their positions is \(15 - 11 = 4\). So, the pattern for the first letter is an increment of 4 positions. The next letter should be the letter 4 positions after O. O is the 15th letter, so \(15 + 4 = 19\). The 19th letter in the alphabet is S.
The second letters in the series are I, M. Let's find their positions in the English alphabet.
The difference in their positions is \(13 - 9 = 4\). So, the pattern for the second letter is also an increment of 4 positions. The next letter should be the letter 4 positions after M. M is the 13th letter, so \(13 + 4 = 17\). The 17th letter in the alphabet is Q.
The next number is 19. The next first letter is S. The next second letter is Q.
Therefore, the next term in the series is 19SQ.
D) 19SQ — This option matches our derived pattern for the number (19), the first letter (S), and the second letter (Q).
The question asks for the object position in a concave mirror that produces a real, inverted image of the same size as the object, located at the center of curvature (C). This is a standard case in ray optics for concave mirrors.
A) At C — When an object is placed at the center of curvature (C) of a concave mirror, the image formed is real, inverted, and of the same size as the object. The image is also located at C.