This problem involves calculating a constant distance based on varying speeds and the corresponding time differences. We can use the fundamental relationship between distance, speed, and time, and set up equations based on the given scenarios.
B) 16.8 km is the calculated distance.
This is a syllogism problem. We can solve it using Venn diagrams or by applying rules of syllogism. The goal is to determine which conclusions logically follow from the given statements.
Analyze Statement 1: All parrots are camels.
Analyze Statement 2: All camels are wolves.
Combine the statements:
Evaluate Conclusion 1: Some parrots are not wolves.
Evaluate Conclusion 2: Some wolves are parrots.
Correct Option: D) Only (2) follows
This problem involves the concept of work and efficiency. We need to establish a relationship between the work done by experts and trainees, then use this relationship to find the equivalent number of trainees for a given number of experts to complete a similar work in the same duration.
The problem states that 15 experts can do as much work as 25 trainees in a given period of time. This means their work rates are proportional.
\[ 15 \text{ Experts} = 25 \text{ Trainees} \]Divide both sides of the equation by 15 to find out how many trainees are equivalent to 1 expert:
\[ 1 \text{ Expert} = \frac{25}{15} \text{ Trainees} \]\[ 1 \text{ Expert} = \frac{5}{3} \text{ Trainees} \]The work is to be done by 8 experts and 15 trainees. Convert the experts into an equivalent number of trainees:
\[ 8 \text{ Experts} = 8 \times \frac{5}{3} \text{ Trainees} = \frac{40}{3} \text{ Trainees} \]Total trainees for the first group = (Trainees from experts) + (Actual trainees)
\[ \text{Total Trainees}_1 = \frac{40}{3} + 15 \]\[ \text{Total Trainees}_1 = \frac{40 + (15 \times 3)}{3} = \frac{40 + 45}{3} = \frac{85}{3} \text{ Trainees} \]The second scenario involves 11 experts and an unknown number of trainees, say \(x\). Convert the 11 experts into an equivalent number of trainees:
\[ 11 \text{ Experts} = 11 \times \frac{5}{3} \text{ Trainees} = \frac{55}{3} \text{ Trainees} \]Since the work is similar and the duration is the same, the total equivalent number of trainees must be the same for both scenarios.
\[ \text{Total Trainees}_1 = \text{Total Trainees}_2 \]\[ \frac{85}{3} = \frac{55}{3} + x \]Subtract \(\frac{55}{3}\) from both sides to find the number of additional trainees needed:
\[ x = \frac{85}{3} - \frac{55}{3} \]\[ x = \frac{85 - 55}{3} \]\[ x = \frac{30}{3} \]\[ x = 10 \text{ Trainees} \]A) 10. The calculation shows that 10 trainees are needed alongside 11 experts to complete the same amount of work in the same duration.
Which of the following statements is/are true?
A. Rigidity: It is the property of matter to maintain its shape even if external force acts on it and solids show this property.
B. Fluidity: It is the property of a substance to easily flow and allow change in its shape under external forces and this property is exhibited both by liquids and gases.
Only A is true
A and B both are true
A and B both are false
Only B is true
The question asks to identify the true statements regarding the properties of matter: rigidity and fluidity. We need to evaluate each statement based on the definitions of these properties and how they apply to different states of matter (solids, liquids, gases).
Correct Option: B) A and B both are true
While whitewashing, Ca(OH)2 reacts slowly with CO2 in air to form a thin layer of _____ on the walls.
The question describes a common chemical reaction that occurs during whitewashing. Whitewashing involves applying a solution of calcium hydroxide, \(\text{Ca(OH)}_2\), to walls. This solution then reacts with carbon dioxide, \(\text{CO}_2\), present in the air to form a solid layer. We need to identify the chemical compound that forms this thin layer.
Correct Option: D) The reaction between calcium hydroxide \(\text{Ca(OH)}_2\) and carbon dioxide \(\text{CO}_2\) produces calcium carbonate \(\text{CaCO}_3\), which forms the thin, shiny layer on the walls after whitewashing.
Who was included in Badminton Association of India's coach panel in 2017?
The question asks us to identify the badminton player who was included in the Badminton Association of India's (BAI) coaching panel in 2017. To answer this question, we need to recall the coaching panel announced by BAI in June 2017 and identify which of the given players was selected.
Understand the Badminton Association of India:
The Badminton Association of India (BAI) is the national governing body responsible for promoting, organising, and developing badminton in India.
It oversees national competitions, coaching programmes, and the development of badminton players across the country.
Understand the coaching panel announced in 2017:
On June 29, 2017, BAI announced a coaching panel that included several former badminton players.
Pullela Gopichand continued as the Chief National Coach, while other experienced players were selected to guide badminton players across different categories and regions.
Identify the prominent members of the coaching panel:
The panel included several former badminton players, such as:
Jwala Gutta was included among the four coaches selected for the women's doubles category.
Understand Jwala Gutta's achievements:
Jwala Gutta is a former Indian badminton player who specialised in doubles events.
She won a bronze medal in women's doubles at the 2011 BWF World Championships with Ashwini Ponnappa.
Her experience and achievements in doubles badminton made her a notable member of the 2017 coaching panel.
Identify the correct answer:
Among the given options, Jwala Gutta was included in the Badminton Association of India's coaching panel in 2017.
Therefore, Jwala Gutta is the correct answer.
Correct Option: D) Jwala Gutta — The Badminton Association of India included former doubles specialist Jwala Gutta in its coaching panel announced on June 29, 2017. She was selected as one of the coaches for women's doubles, alongside Madhumita Bisht, Pradnya Gadre, and Oli Deka. Hence, Option D is the correct answer.
A) Saina Nehwal: This is incorrect because Saina Nehwal was a prominent Indian singles badminton player but was not among the coaches selected for the BAI coaching panel announced in June 2017. She is known for winning a bronze medal at the 2012 London Olympics.
B) PV Sindhu: This is incorrect because PV Sindhu was an active international singles badminton player and was not included in the announced coaching panel. She won a silver medal at the 2016 Rio Olympics.
C) KM Anisha: This is incorrect because KM Anisha was not listed among the coaches appointed to the BAI coaching panel in 2017. Jwala Gutta was the player among the given options whose inclusion was reported.
The question asks to identify the Prime Minister of China as of 2018. This requires knowledge of contemporary political leadership in China.
Correct Option: B) Li Keqiang was the Premier of the State Council of the People's Republic of China from March 2013 to March 2023. Therefore, in 2018, he held the position of Prime Minister (Premier) of China.
Choose the best suitable Venn diagram for the following words:
“Flowers, Fruits, Leaves”
To determine the best Venn diagram for "Flowers, Fruits, Leaves," we need to consider the relationship between these categories. Each category is distinct and does not overlap with the others directly.
Correct Option: A) The diagram shows three separate circles within a square, representing the distinct nature of Flowers, Fruits, and Leaves.
If the roots of the quadratic equation x2 + kx + 9 = 0 are equal, then find the value of k?
To find the value of \(k\) for which the roots of a quadratic equation are equal, we need to use the discriminant property. For a quadratic equation of the form \(ax^2 + bx + c = 0\), the roots are equal if and only if its discriminant, \(\Delta = b^2 - 4ac\), is equal to zero.
C) \(\pm 6\) is the correct value for \(k\) that makes the roots of the given quadratic equation equal.
The question asks to identify the substance where each carbon atom is bonded to four other carbon atoms, forming a rigid three-dimensional structure. This describes a specific allotrope of carbon with a characteristic bonding arrangement.
Correct Option: C) Diamond
In diamond, each carbon atom is \(sp^3\) hybridized and covalently bonded to four other carbon atoms in a tetrahedral geometry. This forms a giant covalent network structure that is very rigid and strong, explaining its hardness and high melting point.
